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    how does the above =
    tan2x = 1
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    Divide both sides by \cos 2x and you obtain \tan 2x = -1

    edit: when division by \cos 2x isn't allowed, i.e. when \cos2x = 0,x = k\pi+\frac{\pi}{2}, it is clear that \tan 2x = -1 and \sin 2x = -\cos 2x
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    (Original post by IShouldBeRevising_)


    how does the above =
    tan2x = 1
    It doesn't.
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    (Original post by hassi94)
    It doesn't.
    tan 2x = -1 *
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    (Original post by IShouldBeRevising_)
    tan 2x = -1 *
    Divide both sides by cos2x.

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