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integration

How do I do the following intergral?

(between 0 and t) ∫ (8+8cos t)^1/2 dt
Reply 1
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BCHL85
12
Note that 1+cost = 2(cos(t/2))^2
Reply 2
Avatar for dhokes
dhokes
OP
13
BCHL85
Note that 1+cost = 2(cos(t/2))^2


Okay thanks, so how would I integrate:

(between 0 and t) 16 ∫ cos^2 (t/2) dt ?
dhokes
How do I do the following intergral?

(between 0 and t) ∫ (8+8cos t)^1/2 dt

∫(8+8cos t)^1/2 dt
1 + cost = 2cos^2(t/2)

= ∫(16cos^2(t/2))^1/2 dt
= ∫4cos(t/2) dt
Reply 4
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dhokes
OP
13
Thanks everyone!

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