[asarwar_95]

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[Math12345]

(Original post by asarwar_95)
Hi. This is a simple 1 mark Question that I unfortunately cant do. Maybe I am overlooking something can someone explain why this is.

Given that 5 sin (theta) = 2cos (theta) Find the value of tan (theta)?

I know sin(theta) / cos (theta) is tan (theta). Therfore shouldn't the answer be 5/2 as it is 5sin(theta equalling 2cos(theta)? The mark scheme says 2/5 instead. Can someone please explain why this is?

sin(theta)/cos(theta) = 2/5 - This is right.

Divide each side by cos theta then divide by 5.

[cheesecake11]

think about this. this kinds always result in an equation in terms of tan. you have cos theta on both sides and sin/cos =tan.
what can you do with that annoying cos on the other side?

[asarwar_95]

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[steve2005]

(Original post by asarwar_95)
Hi. This is a simple 1 mark Question that I unfortunately cant do. Maybe I am overlooking something can someone explain why this is.

Given that 5 sin (theta) = 2cos (theta) Find the value of tan (theta)?

I know sin(theta) / cos (theta) is tan (theta). Therfore shouldn't the answer be 5/2 as it is 5sin(theta equalling 2cos(theta)? The mark scheme says 2/5 instead. Can someone please explain why this is?

No the answer is 2/5. If in doubt take it one step at a time.

[asarwar_95]

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