how do we know about electron orbitals?

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  1. s.aley's Avatar
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    how do we know about electron orbitals?
    no
    Last edited by s.aley; 08-02-2013 at 17:18.
  2. VisualKiddy's Avatar
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    Re: how do we know about electron orbitals?
    The same way we know about atoms. Or bonds. Or literally (nearly almost prettymuch) any physics.
  3. EierVonSatan's Avatar
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    Re: how do we know about electron orbitals?
    Orbitals are just a type of discrete energy level, which have been observed spectroscopically. The theory describing them and their properties is based upon these observations.
  4. Bradshaw's Avatar
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    Re: how do we know about electron orbitals?
    There are a few postulates in Quantum Mechanics that can't be derived. Assuming these are correct, orbitals, amongst lots of other things, come out of the maths. As EVS mentioned, there have been no experimental discrepancies between the QM predictions and experiment, so it is pretty likely that the postulates are correct!
  5. tory88's Avatar
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    Re: how do we know about electron orbitals?
    Quantum physics makes several statements that aren't proved (postulates) - to be honest, they were just educated guesses really. But they were found to work with all experiments conducted and to explain a lot of unexplained phenomena at the time, so are accepted to be true until disproved (as with all science really). Mathematical manipulation of these postulates leads to energy levels that are quantised I.E. have discrete values.
  6. Bradshaw's Avatar
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    Re: how do we know about electron orbitals?
    (Original post by s.aley)
    how exactly
    The orbitals are derived from the time independent Schrodinger Equation for the hydrogen atom:

     -\frac{\hbar^2}{2m}\nabla^2 \psi(r,\theta,\phi) -\frac{\psi(r,\theta,\phi)}{r}=E \psi (r,\theta,\phi)
  7. oli_G's Avatar
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    Re: how do we know about electron orbitals?
    (Original post by Bradshaw)
    The orbitals are derived from the time independent Schrodinger Equation for the hydrogen atom:

     -\frac{\hbar^2}{2m}\nabla^2 \psi(r,\theta,\phi) -\frac{\psi(r,\theta,\phi)}{r}=E \psi (r,\theta,\phi)
    This
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