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Chemical Kinetics help?

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Applying to Uni? Let Universities come to you. Click here to get your perfect place 20-10-2014
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    I have this question about the kinetics of a reaction reaching equilibria and it asks to work out Kf.

    Kf= forward reaction constant
    Kb= backward reaction constant
    Ke= rate constant at equilibrium = 0.0235

    Ke = Kf + Kb
    Kb=0.0235-Kf
    Kf / Kb =2.125
    hence Kf/0.0235 - Kf = 2.125

    The answer for Kf is 0.016, however i can't seem to solve the last equation to get that answer, could someone go step by step on the last equation at how they got to that answer, please
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    well the last equation isn't right, if you put kf = 0.016 into it, you don't get 2.125 so you've done something wrong in your working somewhere

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