[Oromis263]

(Original post by 1platinum)
If you include that question, I think I have only lost 8 marks max, which is ok. After all C3 and C4 determine the A*! Are you feeling prepared for them?

I sat C3 in January and got 100, but I've done very little prep. for C4 so far. Got FP2 next Thursday

[1platinum]

(Original post by Oromis263)
I sat C3 in January and got 100, but I've done very little prep. for C4 so far. Got FP2 next Thursday

Nice, and that was a pretty solid paper! Any tips on C3?

[Oromis263]

(Original post by 1platinum)
Nice, and that was a pretty solid paper! Any tips on C3?

Erm, well off the top of my head, I can only vaguely recall what topics it covered. Just in general make sure you know your integration methods etc, and check answers with a calculator (one that can numerically integrate is a life-saver) when you can!

[Xenite]

Annoyed with myself now.. Pretty sure I aced all the paper, apart from 1b...

I misread 'West' as 'East' and put the bearing as 022.1 (or something like that)... Wonder whether it'll be 1 or 2 of the 3 marks dropped for that.. ah well.

[x_Raman_96]

(Original post by 1platinum)
That's what I got, but apparently there is another method and people have ended up with 1.41 instead.

no i think we are correct

[x_Raman_96]

(Original post by Oromis263)
I'm probably incorrect then. Your method finds when the particle is located south-east of the origin, rather than when it's velocity is in a south-east direction. However, it did seem rather ambiguously worded, I swear it asked for speed when it's motion was in that direction, rather than speed when it was located there. However, a lot of people have done either one or the other, so they may give marks for either method. Argh

I made I = -j, then inserted the time in to the velocity and did Pythagoras, and got the speed of 5. something. it was Square root (5^2)+(3^2)

[1platinum]

(Original post by Xenite)
Annoyed with myself now.. Pretty sure I aced all the paper, apart from 1b...

I misread 'West' as 'East' and put the bearing as 022.1 (or something like that)... Wonder whether it'll be 1 or 2 of the 3 marks dropped for that.. ah well.

I did the exact same thing with Q1b.

(Original post by x_Raman_96)
no i think we are correct

Are you sure? More people say they got 1.41, however plenty of people still got 5.83.

[karchun]

(Original post by 1platinum)
I did the exact same thing with Q1b.



Are you sure? More people say they got 1.41, however plenty of people still got 5.83.

And very few said 3.4-- (Oh I guess I'm the only one) xD

This was posted from The Student Room's Android App on my GT-N7000

[croasdaj]

(Original post by x_Raman_96)
I made I = -j, then inserted the time in to the velocity and did Pythagoras, and got the speed of 5. something. it was Square root (5^2)+(3^2)

The answer is 1.41, my teacher went through it. You get t=20, then you sub that back into v=u+at to get velocity vector 1i + -1j. Magnitude of that is 1.41. All the other answers appear right. For the assumptions I put no air resistance and modelled as a particle

[x_Raman_96]

(Original post by croasdaj)
The answer is 1.41, my teacher went through it. You get t=20, then you sub that back into v=u+at to get velocity vector 1i + -1j. Magnitude of that is 1.41. All the other answers appear right. For the assumptions I put no air resistance and modelled as a particle

NO

[croasdaj]

Sorry to break it to you but YES

[x_Raman_96]

(Original post by croasdaj)
The answer is 1.41, my teacher went through it. You get t=20, then you sub that back into v=u+at to get velocity vector 1i + -1j. Magnitude of that is 1.41. All the other answers appear right. For the assumptions I put no air resistance and modelled as a particle

I am 100% sure, the answer is 5.83

[x_Raman_96]

(Original post by croasdaj)
Sorry to break it to you but YES

Tell me your exact working out! digit for digit

[AntyCole]

(Original post by croasdaj)
The answer is 1.41, my teacher went through it. You get t=20, then you sub that back into v=u+at to get velocity vector 1i + -1j. Magnitude of that is 1.41. All the other answers appear right. For the assumptions I put no air resistance and modelled as a particle

it already stated it was a particle..

[AntyCole]

(Original post by x_Raman_96)
I am 100% sure, the answer is 5.83

its definatly 5.8...

[AntyCole]

(Original post by nmudz_009)
Thank God!!!! u sure yea? cos I know for a fact I got much less than 90 in m1. Not that I'm confident about getting 90+ in c4, but its good to know it's still possible to get an A*

definatly

[croasdaj]

It is 1.41 I am certain. My teacher went through it!!!!

[SGodfrey]

I made a massive mistake for the one where you had to find the speed when the object was travelling south east, I did all the working for when its travelling North east. I also put the range of time when y is above 5 metres as an inequality. How many marks do you estimate I will have lost for these mistakes?

[x_Raman_96]

(Original post by croasdaj)
It is 1.41 I am certain. My teacher went through it!!!!

To be honest, I don't care if your teacher done it. He could've easily made mistakes. I think he is incorrect. You are entitled to your own opinion, but I do not think your views are significant.

[x_Raman_96]

When the boat is travelling south-east the answer is 5.83ms-1