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Identity question

In a worked example I have of an integration it states the integral of (cosx)^2 = the integral of (1 + cos2x)/2

How is this equality reached?

Is this a known identity, (cosx)^2 = (1 + cos2x)/2 ?

Thank you.
Reply 1
Original post by little pixie
In a worked example I have of an integration it states the integral of (cosx)^2 = the integral of (1 + cos2x)/2

How is this equality reached?

Is this a known identity, (cosx)^2 = (1 + cos2x)/2 ?

Thank you.


cos2x=2cos2x1 cos2x = 2cos^2x -1

Rearrange the above expression to get cos2x=1+cos2x2 cos^2x = \dfrac{1+cos2x}{2}
(edited 11 years ago)
Reply 2
Thanks raheem94.

So the first equation you have stated above, is that a well known identity? I don't think I'm aware of that one.
Reply 3
Original post by little pixie
Thanks raheem94.

So the first equation you have stated above, is that a well known identity? I don't think I'm aware of that one.


You must be aware of

cos2(x)+sin2(x)=1\cos^2(x) + \sin^2(x) = 1

and

cos2(x)sin2(x)=cos(2x)\cos^2(x) - \sin^2(x) = \cos(2x).

Combine these.
Reply 4
Original post by little pixie
Thanks raheem94.

So the first equation you have stated above, is that a well known identity? I don't think I'm aware of that one.


Standard re-arrangement of Cos2x

Standard integration method

If you are not aware then you have not been well taught (or you have not been attentive)

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