A question about limits

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  1. anonstudent1's Avatar
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    A question about limits
    Why does [x+y]<= [x] + [y]

    equal

    [x]-[y]<=[x+y]

    where [x] is the modulus/absolute value of x
  2. Hopple's Avatar
    • TSR Idol
    • Location: London
    Re: A question about limits
    Rewrite x+y as a, and y as -b, and see what comes out.
  3. nohomo's Avatar
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    • Posts: 662
    Re: A question about limits
    (Original post by anonstudent1)
    Why does [x+y]<= [x] + [y]

    equal

    [x]-[y]<=[x+y]

    where [x] is the modulus/absolute value of x
    I will show that |x+y| \le |x|+|y| and |x|-|y| \le |x+y| are equivalent. First, set x = X+Y,y = -Y in |x+y| \le |x|+|y| to obtain |X| \le |X+Y|+|-Y| = |X+Y|+|Y|. Then, set x = X+Y,y = -Y in |x|-|y| \le |x+y| to obtain |X+Y|-|Y| = |X+Y|-|-Y| \le |X|.
  4. anonstudent1's Avatar
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    Re: A question about limits
    (Original post by Hopple)
    Rewrite x+y as a, and y as -b, and see what comes out.
    [a]<=[x]-[b]

    [x]+[b]<=[a]
  5. Hopple's Avatar
    • TSR Idol
    • Location: London
    Re: A question about limits
    (Original post by anonstudent1)
    [a]<=[x]-[b]

    [x]+[b]<=[a]
    x = a+b, and |-b| = |b| Also, how did you get from the first line of that to the second?
  6. anonstudent1's Avatar
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    • Posts: 976
    Re: A question about limits
    (Original post by Hopple)
    x = a+b, and |-b| = |b| Also, how did you get from the first line of that to the second?
    Ok i get i understand now. Thanks for your help!
  7. anonstudent1's Avatar
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    • Posts: 976
    Re: A question about limits
    (Original post by Hopple)
    x = a+b, and |-b| = |b| Also, how did you get from the first line of that to the second?
    Wait sorry i don't understand lol

    Ok so i get

    [a]<= [a+b] - [b]

    How do i go from there to get

    [a+2b] <= [x]+[y]

    ?
  8. Hopple's Avatar
    • TSR Idol
    • Location: London
    Re: A question about limits
    (Original post by anonstudent1)
    Wait sorry i don't understand lol

    Ok so i get

    [a]<= [a+b] - [b]

    How do i go from there to get

    [a+2b] <= [x]+[y]

    ?
    nohomo's basically written it all out, but doing as I said, you'll get the first inequality becoming |a| <= |a+b| + |b|
  9. anonstudent1's Avatar
    • Exalted and Worshipped Member
    • Posts: 976
    Re: A question about limits
    (Original post by nohomo)
    I will show that |x+y| \le |x|+|y| and |x|-|y| \le |x+y| are equivalent. First, set x = X+Y,y = -Y in |x+y| \le |x|+|y| to obtain |X| \le |X+Y|+|-Y| = |X+Y|+|Y|. Then, set x = X+Y,y = -Y in |x|-|y| \le |x+y| to obtain |X+Y|-|Y| = |X+Y|-|-Y| \le |X|.
    Thank you!
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