[d_94]

(Original post by bahjat93)
It's all good right? the website seems a bit iffy

Iffy?? Whatt?

[bahjat93]

(Original post by iesians)
ok how can you prove SHM by looking at the desplacemnt time graph and acceleration time graph ..?!

I'm with AQA but i think the answer is going to be the same for you .
There are 2 things that must happen for a system to be in SHM.
The acceleration must be proportional to the displacement and the acceleration must be in the opposite direction to the displacement.

Linking this to your displacement time graph and lets say that the Displacement time graph starts at 1 and if the acceleration graph starts from -1 the system can be described as being in SHM.

[bahjat93]

(Original post by d_94)
Iffy?? Whatt?

DW i've downloaded it .
Are these your notes??
Hopefully they will be able to help me out too

[d_94]

(Original post by bahjat93)
DW i've downloaded it .
Are these your notes??
Hopefully they will be able to help me out too

Nopee. I didnt write them, but they're amazing. I studied all of those notes.

[fluteflute]

Wanted to create a thread specific to this module

[savouryjesus]

Makes sense.
Anyone got a jan 12 paper/ms for this module?

[heretolearnscience]

Hey mates I'm looking for a link from which i can download all the Unit 5 papers up to June 2011, if anyone has come across any such link please let me know. Will be much appreciated Cheers!
Also if anyone has any questions on Unit 5 please do ask, i'll be more than happy to help, it'll also get my rusty old Unit 5 repertoire running, been focused on Unit 4 too much of late

[heretolearnscience]

(Original post by savouryjesus)
Makes sense.
Anyone got a jan 12 paper/ms for this module?

Here you go mate, look for the Physics column, download "Physics QP Jan 2012" and "Physics MS Jan 2012" they've got all the units for Physics:
http://www.xtremepapers.com/communit...all-gce.11898/

[savouryjesus]

(Original post by heretolearnscience)
Here you go mate, look for the Physics column, download "Physics QP Jan 2012" and "Physics MS Jan 2012" they've got all the units for Physics:
http://www.xtremepapers.com/communit...all-gce.11898/

Thank you! that's great
So what topic do people think is the hardest in unit 5?

[attiyatanvir]

i didnt even start p5 have maths c3 n how was p4 i had sooo gud practice n paper was worst

[584385]

Unit 5 papers

[584385]

Mark Schemes

[Parthenon93]

Anyone with the June 2011 QP?

[heretolearnscience]

(Original post by attiyatanvir)
i didnt even start p5 have maths c3 n how was p4 i had sooo gud practice n paper was worst

Unit 4 was ok, could have been better, Q17 b) c) and d) i didn't like, also the last few questions of Q18 were kinda annoying but i reckon it went well compared to the Jan Unit 4 paper.
I have C3 coming up as well. The paper that really stresses me though is C4.

[Jess!ca]

Can someone help with this Q >~< its on thermal energy:

A 500g ball of copper at 75 degrees c is cooled by dropping it into 300g water at 20 degrees c. Assuming no heat is lost, what will be the equilibrium temp?

Specific heat capacities: copper 390, water 4200.

Any help would be appreciated!!

[wojmeister97]

(Original post by Jess!ca)
Can someone help with this Q >~< its on thermal energy:

A 500g ball of copper at 75 degrees c is cooled by dropping it into 300g water at 20 degrees c. Assuming no heat is lost, what will be the equilibrium temp?

Specific heat capacities: copper 390, water 4200.

Any help would be appreciated!!

Hi, I think this is how you would answer your quetion

ΔE= mcΔθ

Energy lost by copper= energy gained by water

Equate the equations for water and copper:
0.5x390xΔ(θ for copper) = 0.3x4200xΔ(θ for water)
Δ(θ for copper)/Δ(θ for water) =6.46 (rearranging the equation above)

So copper loses 6.46 X the temperature gained by water

75 degrees celcius - 20 degrees celcius = 55 degrees celcius

Using ratios:
Δ(θ for copper):Δ(θ for water) = 6.46:1

Δ(θ for copper) = 6.46/(6.46+1)x55=47.6 degrees celcius loss in temperature
Δ(θ for water) = 1/(6.46+1)x55= 7.4 degrees celcius gain in temperature

So, equillibrium temperature = 20 (starting temp. of water) + 7.4 = 27.4 degrees C
OR
equillibrium temperature = 75 (starting temp. of copper) - 47.6 = 27.4 degrees C

Hope i've helped

[Parthenon93]

Can anyone help me understand how to calculate the mass deficit of an atom?

There is a worked example in page 139 of the Miles Hudson book of a proton-proton chain reaction.

I cannot understand how they calculated the mass of the He nucleus to be 4.002602u!

[Birterillo]

Does anyone know how much synoptic content can be covered in this exam?

[cisne]

anybody here????

[King_Arthur]

(Original post by cisne)
anybody here????

ya but this thread isn't that happening >>>>>