[Hazwanfakhri]

(Original post by xiyangliu)
Your method is correct but answer appears to be different from most of ppl ...


This was posted from The Student Room's iPhone/iPad App

yeahh i compared answers with my friends and they got the same answer as discussed here. i might have done a silly calculator mistake.

so how many marks do you think i would lose?

[xiyangliu]

(Original post by Hazwanfakhri)
yeahh i compared answers with my friends and they got the same answer as discussed here. i might have done a silly calculator mistake.

so how many marks do you think i would lose?

Not sure but u ll get all method marks


This was posted from The Student Room's iPhone/iPad App

[posting]

has any1 made a markscheme yet?

[firebolt]

(Original post by posting)
has any1 made a markscheme yet?

Theres a markscheme already been made on this thread

[bluekipper]

(Original post by posting)
has any1 made a markscheme yet?

(Original post by xiyangliu)
1)(A) FALSE (B)True (C)True (D)False
2)(i)v=3t^2-12t+9
(ii)s=t^3-6t^2+9t-2
3)(i)(0,0)
(ii) (A): equilibrium (B): zero Displacement
4)(i) using s=ut+o.5at^2
500=5x20 + 0.5a400
a = 2
(ii)v = 35
5)(i) hope you got that right, tension, Reaction, friction and weight
(ii)25
(3)50cos30+R=10g solve for R
(IV) NOT SURE
6)(i) 3.57 some thing like this therefore over
(ii) air resistance
7)(i) R =1500
(ii) (A) 5900N (B)100300N
(iii)121000-( 800000g x 1/80 + 33000) = - 0.0125 direction down the slope
(iv) beta = 0.241 (3sf)
8)(i) Abs(AB) which use pythagoras (12,16)
(ii) differentiat r = (3,2) + (6,8)t should get (6,8) therefore constant velocity
(iii) cant remember ...
(iv) finishes the race at the same time
(v) differentiate get speed is (6,8t), sub t = 2 into it get (6, 16) pythag again get speed which is abt 17 bearing is 021
(vi) S1 - S2, horizontal displacement cancels out
Verticle you get 4t^2 - 8t... differentiate this get 8t - 8, make this to 0 get maximum point
get t = 1
sub bak in, get greatest distance is 4km

Does anyone have the paper please?

[shredfest]

(Original post by TimetoSucceed)
guys i did the projectile differently

i did s = ut + o.5at^2

set s as 2.44, used quadratic formula to get t, got 2 values

used the highest one and that was when it was descending

used that t to work out the horizonal distance at that time which was 55m

therefore as 55>50, and 2.44 is the vertical distance off the ground at 55m, then at 50m itd be above 2.44 hence going over the pole.

Sounds good to me!
you made such a meal out of it hahaha, but thats whats good about M1 you can use a variety of methods.

[purpleelement]

(Original post by xiyangliu)
Last question was dodge did anyone get beta as 0.241 3sf


This was posted from The Student Room's iPhone/iPad App

Yes!

[shewhomustnotbnamd]

two questions, 1, do you think i'll lose a mark for constantly putting metres rather than kilometres? and secondly what was q5i) that we're all supposed to have got?!

[DavidH20]

(Original post by shewhomustnotbnamd)
two questions, 1, do you think i'll lose a mark for constantly putting metres rather than kilometres? and secondly what was q5i) that we're all supposed to have got?!

You might have lost one mark, but you'll only be penalised once for the mistake. As for q5(i), I believe that was a force diagram of a block being pulled by a string

[shewhomustnotbnamd]

(Original post by DavidH20)
You might have lost one mark, but you'll only be penalised once for the mistake. As for q5(i), I believe that was a force diagram of a block being pulled by a string

ahh thanks so much ) annoying about the metres kilometres thing if the maths is right though...its a maths test not a reading test -_- same with the comprehension in c4, wheres the fricking algebra in english a level?! but thanks sorry for the rant :P x