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FP1 OCR (not MEI) 1st June Exam Discussion

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Original post by h2shin
if cos theta = 0.5, and sin theta = -Sqrt3/2 then the angle that satisfies both these is -60 degrees, and since we evaluated it as rotation anti-clocwise, a negative angle is rotation clockwise...


So it was clockwise?

Thats what i put but now im confused.... :confused:
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h2shin
9
Original post by Alex Newton
So it was clockwise?

Thats what i put but now im confused.... :confused:


yeah, I thought you said it was anti clockwise..
(edited 11 years ago)
Original post by Bless3d
I was having fun...you could have at least waited a while longer :frown:


Hahaha, sorry xD
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linnet18
Anyone got a copy of the paper?
Original post by ninuzu
Quite a nice paper actually, and was very pleased with myself :biggrin: The grade boundary for an A in this paper was 65/72!!!
http://pdf.ocr.org.uk/download/admin/ocr_64986_admin_unit_grd_bound_jan_12.pdf?


how did you fully factorise question 4? i got 0.25n^2(n+1)^2- 1.5n(n+1)....
Original post by Kitnimohabbathai
how did you fully factorise question 4? i got 0.25n^2(n+1)^2- 1.5n(n+1)....


Can't remember exactly and not looking at the q but certain that (n+1)^2 is (n+i)(n-i) <-- that cost me two UMS :angry:
Original post by BobGreggary
Oh god don't tell me this! XD

If you like I'll send you this file I've made which basically has all the FP1 papers from 2012 Jan to 2005 June with all the questions organised into chapters (excluding Ch.1 which I've kind of mixed with Chapter 10).

Good luck with your studying regardless :biggrin:


do you still have that file by any chance? I have my FP1 exam in june and i would really appreciate it if you could send it to me...

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