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# FP1 OCR (not MEI) 1st June Exam Discussion

Maths exam discussion - share revision tips in preparation for GCSE, A Level and other maths exams and discuss how they went afterwards.

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1. Re: FP1 OCR (not MEI) 1st June Exam Discussion
(Original post by crazymanny00)
if you have the FP1 book by OCR (Douglas quadling.. something) on page 30 there is an explanation on how this is done. It's a lengthy process but you get there...

Attachment 153037
Ah thanks, I get it now
2. Re: FP1 OCR (not MEI) 1st June Exam Discussion
hey guys am i right in saying that for cubic roots...
1.alpha + beta + gamma = -b/a
2.(alpha x beta) + (alpha x gamma) + (beta x gamma) = c/a
3.Alpha x beta x gamma = -d/a
3. Re: FP1 OCR (not MEI) 1st June Exam Discussion
thats right yeah
4. Re: FP1 OCR (not MEI) 1st June Exam Discussion
If so than for january 2012 exam paper Q10)(ii) i substituted x = sqrt(u). and got the correct equation as shown in the mark scheme...
" 9u^3 - 45u^2 + 72u - 4 " this is definitely correct, the mark scheme says so, but how can c = -4/9 because " alpha x beta x gamma = -d/a, so should it not be just 4/9???
5. Re: FP1 OCR (not MEI) 1st June Exam Discussion
i posted on that one earlier... i think it's because they started a on the x squarer coefficient not the x cubed and you had to use c/a not -d/a .... much confusion and trickery, but thats OCR for you
Last edited by crazymanny00; 31-05-2012 at 21:41.
6. Re: FP1 OCR (not MEI) 1st June Exam Discussion
look here is what the mark scheme says for it but i do not understand, they have done the same thing for a.
7. Re: FP1 OCR (not MEI) 1st June Exam Discussion
EVEN " A " is done the weird way, but how comes if they started on the x squared one would the -45 now be the a??
8. Re: FP1 OCR (not MEI) 1st June Exam Discussion
i just dont know...
9. Re: FP1 OCR (not MEI) 1st June Exam Discussion
So..... who's hoping for a hard paper....? :P
10. Re: FP1 OCR (not MEI) 1st June Exam Discussion
you are right though, either were missing something or its wrong.... going more towards the ms being wrong haha
11. Re: FP1 OCR (not MEI) 1st June Exam Discussion
(Original post by RooT_Fifteen)
So..... who's hoping for a hard paper....? :P
for lower grade boundaries? personally i don't think it will be too hard anyway
12. Re: FP1 OCR (not MEI) 1st June Exam Discussion
LAST one to go , then halfterm!!!
anyone same???
13. Re: FP1 OCR (not MEI) 1st June Exam Discussion
(Original post by crazymanny00)
for lower grade boundaries? personally i don't think it will be too hard anyway
i'm not sure.. given ocr's other maths exams this year, i think my money is on it being a hard paper
14. Re: FP1 OCR (not MEI) 1st June Exam Discussion
you could be right on that actually... S1 was hard.. i know M2 in jan was hard aswell but sitting that on the 22nd
15. Re: FP1 OCR (not MEI) 1st June Exam Discussion
I can tell you the D1 wasnt nice either (not that it ever is), and ah, good luck! this FP1 is my last exam 'till January
16. Re: FP1 OCR (not MEI) 1st June Exam Discussion

Can someone quickly run through part i?
I can't see how 13^n + 6^(n-1) + 13^(n+1) + 6^n = 14 x 13^(n) + 7 x 6^(n-1)
17. Re: FP1 OCR (not MEI) 1st June Exam Discussion
Can someone please explain what you're meant to do when you're using method of differences then it asks for (sum of r=n+1 to infinity)?? Or if you have r=2 on the bottom of the sigma? I'm still confused.. :/
18. Re: FP1 OCR (not MEI) 1st June Exam Discussion
hey guys, i was doing an induction question and i came to a point where, oh what the heck let me tell you the question.
The sum of ((2^r-1) = ((2^n) -1) from 1 to n
and i got to the stage of ((2^k)-1) + ((2^k+1) -1) where i inputted n = k + 1
and i do not understand how to simplify this to get = ((2^k+1) -1)
if you do not understand my writing could you just try and do the question yourself? if you understand the question?
19. Re: FP1 OCR (not MEI) 1st June Exam Discussion
(Original post by As_Dust_Dances_)
Can someone please explain what you're meant to do when you're using method of differences then it asks for (sum of r=n+1 to infinity)?? Or if you have r=2 on the bottom of the sigma? I'm still confused.. :/
sum r=1 with n=infinity minus sum r=1 n=n i think
20. Re: FP1 OCR (not MEI) 1st June Exam Discussion
hey guys, i was doing an induction question and i came to a point where, oh what the heck let me tell you the question.
The sum of ((2^r-1) = ((2^n) -1) from 1 to n
and i got to the stage of ((2^k)-1) + ((2^k+1) -1) where i inputted n = k + 1
and i do not understand how to simplify this to get = ((2^k+1) -1)
if you do not understand my writing could you just try and do the question yourself? if you understand the question?

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