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Triangle

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    XYZ is a right angle triangle.

    XY=8 cm
    XZ=6 cm
    ZY=10 cm
    Angle x = 90 degrees

    What is the length of the perpendicular distance of x from ZY

    How do I work this question out.

    Do I use COS SIN TAN or something.
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    (Original post by zed963)
    XYZ is a right angle triangle.

    XY=8 cm
    XZ=6 cm
    ZY=10 cm
    Angle x = 90 degrees

    What is the length of the perpendicular distance of x from ZY

    How do I work this question out.

    Do I use COS SIN TAN or something.
    Yeah you can use sohcahtoa

    Specifically that sin(theta) = opp/hyp

    Figure out what sin(theta) is for either angle. Now draw in the perpindicular and you should have a new right angled triangle containing theta, which will give you sin(theta) = L/something (where L is the perpendicular distance you're looking for.

    Alternatively you can use simultaneous equations, area of triangles and probably more methods. You can ask me about those if you'd like, too.
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    (Original post by hassi94)
    Yeah you can use sohcahtoa

    Specifically that sin(theta) = opp/hyp

    Figure out what sin(theta) is for either angle. Now draw in the perpindicular and you should have a new right angled triangle containing theta, which will give you sin(theta) = L/something (where L is the perpendicular distance you're looking for.

    Alternatively you can use simultaneous equations, area of triangles and probably more methods. You can ask me about those if you'd like, too.
    I would equate area. http://www.waldomaths.com/TriArea1NL.jsp
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    (Original post by steve2005)
    I would equate area. http://www.waldomaths.com/TriArea1NL.jsp
    Yeah as I said there are a fair few methods to tackle this question

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