OCR M1 - 31st May 2012 Discussion Thread.

Maths exam discussion - share revision tips in preparation for GCSE, A Level and other maths exams and discuss how they went afterwards.

Announcements Posted on
IMPORTANT: You must wait until midnight (morning exams)/4.30AM (afternoon exams) to discuss Edexcel exams and until 1pm/6pm the following day for STEP and IB exams. Please read before posting, including for rules for practical and oral exams. 28-04-2013
Sign in to Reply
  1. As_Dust_Dances_'s Avatar
    • Benevolent Member
    • Location: England
    • Posts: 635
    OCR M1 - 31st May 2012 Discussion Thread.
    I'm not sure if there's already a thread yet but here's a new one anyway Feel free to post questions and I'll try to answer them. Anyone else finding time graphs annoying?
  2. Soggy Cherry's Avatar
    • Junior Member
    • Posts: 45
    Re: OCR M1 - 31st May 2012 Discussion Thread.
    Hey! Just had a go at the Jan 2012 paper, which I hadn't already done, and there was a question on collisions. Usually I find these ones the easiest on the paper but I couldn't figure this one out and there isn't a detailed mark scheme which has been released yet. Basically: P and Q moving in same direction, P has mass 0.3 and is travelling at 2.2, Q has mass 0.5 and is travelling at 0.8. They collide (obviously) and afterwards 'the speed of P is reduced by 50% and its direction of motion is unchanged'. Find the speed of Q afterwards. Couldn't figure out the right answer, which by the way is apparently 1.46m/s
  3. As_Dust_Dances_'s Avatar
    • Benevolent Member
    • Location: England
    • Posts: 635
    Re: OCR M1 - 31st May 2012 Discussion Thread.
    (Original post by Soggy Cherry)
    Hey! Just had a go at the Jan 2012 paper, which I hadn't already done, and there was a question on collisions. Usually I find these ones the easiest on the paper but I couldn't figure this one out and there isn't a detailed mark scheme which has been released yet. Basically: P and Q moving in same direction, P has mass 0.3 and is travelling at 2.2, Q has mass 0.5 and is travelling at 0.8. They collide (obviously) and afterwards 'the speed of P is reduced by 50% and its direction of motion is unchanged'. Find the speed of Q afterwards. Couldn't figure out the right answer, which by the way is apparently 1.46m/s
    momentum before = momentum after so you should get:

    (0.3 x 2.2) + (0.5x0.8) = (0.3x1.1) + 0.5v (1.1 comes from half of 2.2)

    0.66 + 0.4 = 0.33 + 0.5v

    so 0.5v = 0.73

    so v= 0.73/0.5 => 1.46ms^-1

    Hope that helps I haven't done the Jan12 paper yet so it's also practice for me too!
  4. Soggy Cherry's Avatar
    • Junior Member
    • Posts: 45
    Re: OCR M1 - 31st May 2012 Discussion Thread.
    (Original post by As_Dust_Dances_)
    momentum before = momentum after so you should get:

    (0.3 x 2.2) + (0.5x0.8) = (0.3x1.1) + 0.5v (1.1 comes from half of 2.2)

    0.66 + 0.4 = 0.33 + 0.5v

    so 0.5v = 0.73

    so v= 0.73/0.5 => 1.46ms^-1

    Hope that helps I haven't done the Jan12 paper yet so it's also practice for me too!
    I feel like such an idiot! Did all that but instead of multiplying 1.1 and 0.3, I added them haha, and couldn't even spot it myself! But thanks a lot though Should have a go at it if you could find it then! Though I had to get it from my teacher because I don't think it's allowed to be online yet? As for time graphs, I just struggle finding the displacement when it's a shape I've forgotten how to find the area of, which is my fault and can easily be fixed
    Last edited by Soggy Cherry; 29-05-2012 at 21:45.
Sign in to Reply
Share this discussion:  
Article updates
Moderators

We have a brilliant team of more than 60 volunteers looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

Reputation gems:
The Reputation gems seen here indicate how well reputed the user is, red gem indicate negative reputation and green indicates a good rep.
Post rating score:
These scores show if a post has been positively or negatively rated by our members.