Would appreciate if someone could help on this suvat question, part 3.
A particle P is projected vertically downwards from a fixed point O with initial speed 4.2ms−1, and takes 1.5 s to reach the ground. Calculate
(i) the speed of P when it reaches the ground,
(ii) the height of O above the ground,
(iii) the speed of P when it is 5m above the ground.
I'm stuck on the third part of this question.
I got S as 5 , u as 4.2 , v as v , a as 9.8 .
V^2=U^2+2as , v= root(4.2^2+98) , v=10.7 which is wrong
Thanks , saw where the error was
Unless O is 10m above ground, the s in part iii should not be 5.
Thanks for posting! You just need to create an account in order to submit the post
Already a member?
Oops, something wasn't right
please check the following:
Not got an account?
Sign up now
© Copyright The Student Room 2015 all rights reserved
The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.
Register Number: 04666380 (England and Wales), VAT No. 806 8067 22
Registered Office: International House, Queens Road, Brighton, BN1 3XE