[lee_vassallo]

Hey all -

Exam is in a couple of days and saw no thread for it. This is a resit for me - last chance!

[jammysmt]

I'm in the same boat. Hope it goes better than January, that paper was terrifying.

[lee_vassallo]

They couldn't possibly make it any harder than that, could they? :

[OllyHV]

I'm resitting it too. Can't be any worse than January, especially with me doing FP2 as well on Thursday.

Only need 65 UMS average on this and C4 to get my A

[Stuffcopier]

Finding the papers TERRIFYINGLY DIFFICULT!!


This was posted from The Student Room's iPhone/iPad App

[Raj K]

can someone please help me out lol it;s my calculator..you know the normal Casio one..it normally converts it into fractions by pressing the S-D button (the change button thing) but now it doesnt :/ i may have accidentally pressed the wrong mode set up or something..does anyone know how i can sort that out ..(it just goes into decimals you see i need it in fractions!!) thankssss

[lee_vassallo]

(Original post by Raj K)
can someone please help me out lol it;s my calculator..you know the normal Casio one..it normally converts it into fractions by pressing the S-D button (the change button thing) but now it doesnt :/ i may have accidentally pressed the wrong mode set up or something..does anyone know how i can sort that out ..(it just goes into decimals you see i need it in fractions!!) thankssss

Press shift and mode/set up button then press 1 for "MthIO" You've currently got it set to "LineIO" which is more useful for physics

[lee_vassallo]

January's paper caught a lot of us out, it was just disastrous! Looking over it again though I've managed to do all the questions but in an exam situation it is completely different. Anyone need help with that paper?

[Stuffcopier]

Yep question 6b? Its 9 marks...


This was posted from The Student Room's iPhone/iPad App

[lee_vassallo]

x=cosecθ
dx/dθ=-cosecθcotθ
∴dx=-cosecθcotθ

Integral becomes:

∫_(√2)^2▒〖(-cosecθcotθ)/(〖cosec〗^2 θ√(1-〖cosec〗^2 θ)) dθ〗

∫_(√2)^2▒〖(-cotθ)/(〖cosec〗^ θ√(〖cot〗^2 θ)) dθ〗

∫_(√2)^2▒〖(-1)/(〖cosec〗^ θ) dθ〗

∫_(√2)^2▒〖-sin⁡θ dθ〗

[cosθ] 2¦√2

The next bit is to sub the limits into x=cosecθ and find out theta in radians then put them into cosθ and subtract them accordingly.

[lee_vassallo]

This might make it easier to see

[Raj K]

(Original post by lee_vassallo)
Press shift and mode/set up button then press 1 for "MthIO" You've currently got it set to "LineIO" which is more useful for physics

ohhh no wonderrrr THANKYOUUUUUUUUUUUUUU

[Charliexo93]

worried about this exam. The January one was so awful :'( praying for an easier paper! I swear the examiners just want us to fail

[Stuffcopier]

Thankyou very much for question 6b


This was posted from The Student Room's iPhone/iPad App

[lee_vassallo]

(Original post by Charliexo93)
worried about this exam. The January one was so awful :'( praying for an easier paper! I swear the examiners just want us to fail

As a matter of fact they do! or at least they want the pass rate to go down as its been on the up for the past 20 years or so. Basically, they're keen on separating the A* students from the A students.

[tom472]

I went over the Jan 2012 paper twice in the past few days and I got everything correct each time, incredibly frustrating. I think it was a hard paper but exam nerves played their part.

[Sagacious]

Personally, I hope the paper is as hard as it was in January. I bossed that past-paper and I'm really hoping for full UMS. However, I always make silly mistakes (exam-nerves), so if it is a hard paper, then the grade boundaries will be more generous to me

1 more day of solid revision left, use it wisely guys

Good luck.

[jammysmt]

Anyone else finding AQA web site being slower and more faulty than usual? Won't allow me to open up past paper files for Maths. What a time for it to happen, day before the exam!

[Z REFAN Z]

Can anyone explain to me how to do the question from June 2008 7.c.
The part im stuck on is how they get integral of cos(theta) divided by cos(theta) squared to the power of 3/2 to sec squared theta... :/

[Iepnauy]

(Original post by Z REFAN Z)
Can anyone explain to me how to do the question from June 2008 7.c.
The part im stuck on is how they get integral of cos(theta) divided by cos(theta) squared to the power of 3/2 to sec squared theta... :/

Because on the bottom, Cos^2(theta) becomes Cos^3(theta). Square root it first, then raise it to the power of 3.

That cancels with the top bit so you're left with 1/Cos^2(theta). Which is the same as Sec^2(theta)