Vectors - vector equations

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  1. Nagillum's Avatar
    • Junior Member
    • Posts: 43
    Vectors - vector equations
    Okay, I'm a bit confused here, hoping someone can help clear this up.

    The question is "Points A, B and C have co-ords (0, 5), (9, 8) and (4, 3) respectively.
    a) Find the vector equation for the line joining A and B.
    b) Show that the perpendicular distance from C to line AB is 101/2 "

    I understand the vector equation = a + t(b - a), which works out for me as:
    (0, 5) + t(9, 3)
    But the answer at the back of the book says (0, 5) + t(3, 1)

    I'll be able to answer b) once I know how it works out at the above answer.
    Any help is appreciated
  2. raheem94's Avatar
    • TSR Demigod
    • Posts: 5,512
    Re: Vectors - vector equations
    (Original post by Nagillum)
    Okay, I'm a bit confused here, hoping someone can help clear this up.

    The question is "Points A, B and C have co-ords (0, 5), (9, 8) and (4, 3) respectively.
    a) Find the vector equation for the line joining A and B.
    b) Show that the perpendicular distance from C to line AB is 101/2 "

    I understand the vector equation = a + t(b - a), which works out for me as:
    (0, 5) + t(9, 3)
    But the answer at the back of the book says (0, 5) + t(3, 1)

    I'll be able to answer b) once I know how it works out at the above answer.
    Any help is appreciated
     \begin{pmatrix} 9 \\ 3 \end{pmatrix} is the direction vector, it can be simplified as  \begin{pmatrix} 3 \\ 1 \end{pmatrix}

    It is similar to the gradient, if gradient  = \dfrac64 , this means moving 6 units in the x-direction and 4 units in the y-direction, this is similar to saying move 3 units in the x-direction and 2 units in the y-direction, i.e. Gradient  = \dfrac32

     \begin{pmatrix} 9 \\ 3 \end{pmatrix} = 3 \begin{pmatrix} 3 \\ 1 \end{pmatrix}
    Hence both vectors are parallel, any of them can be used.

    If you are still confused, then plot a point on a graph paper, and then use the vector to get another point on the line, you will see that both represent the same direction.

    Hope it makes sense.
  3. Nagillum's Avatar
    • Junior Member
    • Posts: 43
    Re: Vectors - vector equations
    (Original post by raheem94)
     \begin{pmatrix} 9 \\ 3 \end{pmatrix} is the direction vector, it can be simplified as  \begin{pmatrix} 3 \\ 1 \end{pmatrix}

    It is similar to the gradient, if gradient  = \dfrac64 , this means moving 6 units in the x-direction and 4 units in the y-direction, this is similar to saying move 3 units in the x-direction and 2 units in the y-direction, i.e. Gradient  = \dfrac32

     \begin{pmatrix} 9 \\ 3 \end{pmatrix} = 3 \begin{pmatrix} 3 \\ 1 \end{pmatrix}
    Hence both vectors are parallel, any of them can be used.

    If you are still confused, then plot a point on a graph paper, and then use the vector to get another point on the line, you will see that both represent the same direction.

    Hope it makes sense.
    I read the first sentence and went "OOHHHHHHHHHHHHHHHHH!" and now I feel stupid for not seeing that! Yeah I get it, thanks a lot man, 20 to midnight probably isn't the best time to be doing maths, eh :P
  4. RockEater's Avatar
    • Junior Member
    • Posts: 69
    Re: Vectors - vector equations
    Your answer to the first part is the same as the one in the book, as the vectors (3,1) and (9,3) point in the same direction. [ (9,3) = 3*(3,1) ]
  5. Nagillum's Avatar
    • Junior Member
    • Posts: 43
    Re: Vectors - vector equations
    (Original post by RockEater)
    Your answer to the first part is the same as the one in the book, as the vectors (3,1) and (9,3) point in the same direction. [ (9,3) = 3*(3,1) ]
    Just to confirm something say I had the vector equation:
    (4, 12) + t(9, 3)

    I WOULD be able to cancel down the (9, 3) as it is a direction vector but I WOULD NOT be able to do this to the (4, 12) because it is a position vector...?
  6. raheem94's Avatar
    • TSR Demigod
    • Posts: 5,512
    Re: Vectors - vector equations
    (Original post by Nagillum)
    Just to confirm something say I had the vector equation:
    (4, 12) + t(9, 3)

    I WOULD be able to cancel down the (9, 3) as it is a direction vector but I WOULD NOT be able to do this to the (4, 12) because it is a position vector...?
    Yes, you can simplify the direction vector but not the position vector.
  7. Nagillum's Avatar
    • Junior Member
    • Posts: 43
    Re: Vectors - vector equations
    Okay, cheers guys!
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