[ctw99]

(Original post by ladygabriela97)
what did everyone put for calculating the maximum speed of the miner? What equation?

I thought the exam was quite easy. Well... compared to the past papers anyway.
I got stuck on the miner question too.

You use ek=0.5*m*v2

Gravitational Potential Energy = 13500J
Mass = 90kg

So v2 = 13500/(90*0.5)
So v2 = 13500/45
So v2 = 300
So v = root 300 = 17.320508075688775
And the answer to a "suitable number of significant figures" is 17 m/s or 17.3 m/s or 17.32 m/s

Hope that helps!

[hello my name is]

(Original post by khalidpatel)
unoffical markscheme guys:
Q1. B, has the steepest line/highest gradient
q2. Resultant force at start is zero. Then driving force increases whilst friction force stays the same. Eventually force of friction increases, reducing the resultant force.

2.75 m/s²
q3. Explain why the rod is negative
the rod is negatively charged as the electrons from the woollen cloth have been transferred the rod by rubbing.

The balance reading increases because opposite charges repel
to prove this theory the student would have to do an experiment and collect data in a graph to conclude the results. The student would collect the balance reading data when the rod is at different distances away from the balance. The student should also repeat these results in order to improve reliability

q4. If the hypothesis is correct, what happens to the current?
The current is doubles
variable resistor
why was a line graph used, not a bar chart
it was not in a bar graph as bother variables were continuous
what is the most likely reason for the anomolous result
human error (reading the data incorrectly)

draw the line of best fit
draw line on the graph

yes that is correct the current doubles as the pd doubles eg (used data from graph as example)
d.c. = current flowing in one direction.
Charge = 36,000 coulombs

kinetic energy = 2,160j ( 0.5*120kg * 6m/s2= 2160j)

distance travelled would decrease, because the weight of the body increases therefore more force is required to move the body because :

Velocity = momentum/mass
momentum is not conserved because an external force was applied.
Conservation of momentum is when :
Total momentum before interaction = total momentum after interaction
mass of skateboard = 2.2kg (55kg*0.4=22 22/10= 2.2kg)

mass number = number of protons + number of neutrons
alpha releases two neutrons and two protons whereas beta replaces the neutron with a proton and emits an electron.
212 ........ 208 .... 4
83 bi -> 81 ti + 2 he

alpha and beta cannot produce the same element since the number of neutrons and protons they release vary. In addition, beta releases an electron. Alpha decay and beta decay of 212 bi cannot ever produce the same element as both have different mass and proton numbers

how many marks was the 2.75 ??? Question

[Elshad]

For the speed of the miner i used the kintic enery equation. If you input the values you get:

13500= 1/2 X 90 X V Squared

13500= Square root of 300

Speed= 17.32 m/s

[tintin330]

Just to clarify, I meant this thread to be about the AQA P2 additional science exam for the new 2012-2013 specification. Sorry for not specifying in the title, but I did say it was for higher tier as one of the first few posts. Having said that, it's fine for anyone to discuss any of the physics P2 exams done today, whether it's the hour paper, the 45-min paper, the higher or the foundation.

Thanks to the person who posted the foundation mark scheme - must have taken you ages! I'm sure loads of people will appreciate it, so thanks!

And thank you to everyone who clarified the kinetic energy question, I'm feeling a little more confident about how I did now were there any other questions that people found tricky? x

[ladygabriela97]

(Original post by ctw99)
I thought the exam was quite easy. Well... compared to the past papers anyway.
I got stuck on the miner question too.

You use ek=0.5*m*v2

Gravitational Potential Energy = 13500J
Mass = 90kg

So v2 = 13500/(90*0.5)
So v2 = 13500/45
So v2 = 300
So v = root 300 = 17.320508075688775
And the answer to a "suitable number of significant figures" is 17 m/s or 17.3 m/s or 17.32 m/s

Hope that helps!

Yeah thats what I did, yay!:L

[ladygabriela97]

(Original post by tintin330)
Just to clarify, I meant this thread to be about the AQA P2 additional science exam for the new 2012-2013 specification. Sorry for not specifying in the title, but I did say it was for higher tier as one of the first few posts. Having said that, it's fine for anyone to discuss any of the physics P2 exams done today, whether it's the hour paper, the 45-min paper, the higher or the foundation.

Thanks to the person who posted the foundation mark scheme - must have taken you ages! I'm sure loads of people will appreciate it, so thanks!

And thank you to everyone who clarified the kinetic energy question, I'm feeling a little more confident about how I did now were there any other questions that people found tricky? x

I found the first one really hard:L(the one with the graph) I know apparently it was easy but I'm not sure my answer made sense as I crossed out a lot:L what did you put?

This was posted from The Student Room's Android App on my GT-I9100

[grammar12]

what did everyone do for the resistance question, i think i muffed that one up badly :/

[chapman.]

(Original post by ladygabriela97)
I found the first one really hard:L(the one with the graph) I know apparently it was easy but I'm not sure my answer made sense as I crossed out a lot:L what did you put?

This was posted from The Student Room's Android App on my GT-I9100

I put about the spring having too much weight put on it, which stretched it past the limit of proportionality

I don't think it's right though, as the next question said limit of proportionality:L

[tintin330]

(Original post by ladygabriela97)
I found the first one really hard:L(the one with the graph) I know apparently it was easy but I'm not sure my answer made sense as I crossed out a lot:L what did you put?

I can't remember the question! What did it say?

For the one about limit of proportionality, I put that it has reached it's limit because the force is no longer directly proportional to the extension - is this right?

and for the error, was it meant to be that the extension was already 50mm, but it should have been 0?

[chapman.]

(Original post by tintin330)
I can't remember the question! What did it say?

For the one about limit of proportionality, I put that it has reached it's limit because the force is no longer directly proportional to the extension - is this right?

and for the error, was it meant to be that the extension was already 50mm, but it should have been 0?

It was the one with a graph shaped like

[tintin330]

(Original post by chapman.)
It was the one with a graph shaped like

haha yes! thank you, i appreciate the effort!

what did you put for the error question?

[chapman.]

(Original post by tintin330)
haha yes! thank you, i appreciate the effort!

what did you put for the error question?

Any time, I didn't take gcse art because they said I'm too good at drawing

But I put some rubbish about hyperextending the spring - basically it's wrong oh well:')

[grammar12]

for the error question i put that he measured the length of the spring IN the TOTAL extension of the spring, because extension is just how much it has extended PAST its original length, i hope thats right :/

[khalidpatel]

(Original post by hello my name is)
how many marks was the 2.75 ??? Question

it was worth 2 marks

[hello my name is]

thanks

[maxtate]

(Original post by khalidpatel)
Unoffical markscheme guys:
The balance reading increases because opposite charges repel

It's that like charges repel not opposite, they attract lol

[maxtate]

(Original post by chapman.)
That mark scheme is for foundation tier, judging from other peoples comments on other threads who've done foundation.

LOL of course it's not foundation tier its higher AQA P2, there are two papers, this one (the one which the markscheme has been put up for) was the harder one, some schools got the easier higher paper

[osama2]

hey u know about the car one. question about acceleration in 2 secs.....i wrote that driving force decreases and friction increases which results in a resultant force in the frictio direction.

[laylarose]

for the error throughout investigation question, i put that the extension is measured in millimetres on the graph, as opposed to centimetres, but i now realise that it's measured in metres

[chapman.]

(Original post by maxtate)
LOL of course it's not foundation tier its higher AQA P2, there are two papers, this one (the one which the markscheme has been put up for) was the harder one, some schools got the easier higher paper

Thanks for the concern pal, but this was already sorted out and the thread as a whole was getting more positive. Well done for trying to take it down!


This was posted from The Student Room's iPhone/iPad App