Hey there Sign in to join this conversationNew here? Join for free

Mr M's OCR FSMQ Additional Mathematics Answers May 2012

Announcements Posted on
Study Help needs new mods! 14-04-2014
We're up for a Webby! Vote TSR to help us win. 10-04-2014
    • Thread Starter
    • 114 followers
    Offline

    ReputationRep:
    [Mr M's OCR FSMQ Additional Mathematics Answers May 2012


    1. Quadratic inequality

    (i) 1 \leq x \leq 3 (3 marks)

    (ii) Two shaded circles on or above 1 and 3 with a line joining them (1 mark)


    2. Biased die

    (i) \frac{2101}{3125} (2 marks)

    (ii) \frac{32}{625} (4 marks)


    3. Factors and remainders

    (i) Show a = -7 (2 marks)

    (ii) f(x)=(x-1)(x-2)(x+3) (3 marks)


    4. Constant acceleration

    Distance = 130 metres and acceleration = 0.6 metres per second squared (4 marks)


    5. Trigonometric equation

    (i) Show trigonometric equation (2 marks)

    (ii) Theta = 41.8 degs, 138.2 degs, 270 degs (4 marks)


    6. Stationary point

    (i) Show S.P. when x = 2 (4 marks)

    (ii) Minimum (2 marks)


    7. Yachtsman

    (i) 3.11 km (3 marks)

    (ii) Angle ABC = 61.6 degs and bearing = 152 degs (4 marks)


    8. Integral

    (i) Show value of integral = 2/3 (3 marks)

    (ii) Part of the area is below the x axis and so would have a negative value (1 mark)

    (iii) Area = 4 square units (3 marks)


    9. Fairground

    (i) 2 metres (1 mark)

    (ii) 12 metres (2 marks)

    (iii) 14 seconds (4 marks)


    10. Circle

    (i) Midpoint (4, 6) (1 mark)

    (ii) (x-4)^2 + (y-6)^2 = 25 (4 marks)

    (iii) Show B is on circle (1 mark)

    (iv) Show lines are perpendicular (3 marks)

    (v) (0, 3) (3 marks)


    11. Shaded region

    (i) 2y = x + 6 (5 marks)

    (ii) (3, 4.5) (3 marks)

    (iii) Area = 125/12 (4 marks)


    12. Highway Code

    (i) Show formula (5 marks)

    (ii) 38.75 feet (3 marks)

    (iii) 23.2 mph (4 marks)


    13. Chords

    (i) a=12, b=6, c=1 (3 marks)

    (ii) Show gradient of chord (3 marks)

    (iii) 12+6h+h^2 (2 marks)

    (iv) 12 (1 mark)

    (v) Gradient = 32 +24h+8h^2+h^3

    As h gets close to zero, the gradient becomes ever closer to 32. (3 marks)
    • 0 followers
    Offline

    ReputationRep:
    First, of all, thanks a lot! However, just wondering whether you could have a copy of the paper to scan in - if so it'd be really helpful!
    • 2 followers
    Offline

    ReputationRep:
    YES. OH GOD YESSS

    But you bearing one is wrong. Degree is correct but bearing has to go clockwise from north, i.e. 180 degrees to get to south, 90 degrees more the get to east and then the original degree added to get the bearing.

    So 270 degrees+your degree that you found was the right answer
    • Thread Starter
    • 114 followers
    Offline

    ReputationRep:
    (Original post by CheeseLord)
    First, of all, thanks a lot! However, just wondering whether you could have a copy of the paper to scan in - if so it'd be really helpful!
    It's not my property to scan. Under the terms of our agreement with OCR, I may only use past papers with my own students in my Centre.
    • Thread Starter
    • 114 followers
    Offline

    ReputationRep:
    (Original post by cyfer)
    YES. OH GOD YESSS

    But you bearing one is wrong. Degree is correct but bearing has to go clockwise from north, i.e. 180 degrees to get to south, 90 degrees more the get to east and then the original degree added to get the bearing.

    So 270 degrees+your degree that you found was the right answer
    Sorry my answer is correct. You were asked to find the bearing of B FROM C.
    • 5 followers
    Offline

    ReputationRep:
    (Original post by Mr M)
    [Mr M's OCR FSMQ Additional Mathematics Answers May 2012


    4. Constant acceleration

    Distance = 190 metres and acceleration = 0.6 metres per second squared (4 marks)

    Is Distance not 130m..
    I do not remember the figures but I am sure that the Distance/Answer was 130 :confused:
    • 4 followers
    Offline

    ReputationRep:
    (Original post by Mr M)
    [Mr M's OCR FSMQ Additional Mathematics Answers May 2012


    1. Quadratic inequality

    (i) 1 \leq x \leq 3 (3 marks)

    (ii) Two shaded circles on or above 1 and 3 with a line joining them (1 mark)


    2. Biased die

    (i) \frac{2101}{3125} (2 marks)

    (ii) \frac{32}{625} (4 marks)


    3. Factors and remainders

    (i) Show a = -7 (2 marks)

    (ii) f(x)=(x-1)(x-2)(x+3) (3 marks)


    4. Constant acceleration

    Distance = 190 metres and acceleration = 0.6 metres per second squared (4 marks)


    5. Trigonometric equation

    (i) Show trigonometric equation (2 marks)

    (ii) Theta = 41.8 degs, 138.2 degs, 270 degs (4 marks)


    6. Stationary point

    (i) Show S.P. when x = 2 (4 marks)

    (ii) Maximum (2 marks)


    7. Yachtsman

    (i) 3.11 km (3 marks)

    (ii) Angle ABC = 61.6 degs and bearing = 152 degs (4 marks)


    8. Integral

    (i) Show value of integral = 2/3 (3 marks)

    (ii) Part of the area is below the x axis and so would have a negative value (1 mark)

    (iii) Area = 4 square units (3 marks)


    9. Fairground

    (i) 2 metres (1 mark)

    (ii) 12 metres (2 marks)

    (iii) 14 seconds (4 marks)


    10. Circle

    (i) Midpoint (4, 6) (1 mark)

    (ii) (x-4)^2 + (y-6)^2 = 25 (4 marks)

    (iii) Show B is on circle (1 mark)

    (iv) Show lines are perpendicular (3 marks)

    (v) (0, 3) (3 marks)


    11. Shaded region

    (i) 2y = x + 6 (5 marks)

    (ii) (3, 4.5) (3 marks)

    (iii) Area = 125/12 (4 marks)


    12. Highway Code

    (i) Show formula (5 marks)

    (ii) 38.75 feet (3 marks)

    (iii) 23.2 mph (4 marks)


    13. Chords

    (i) a=12, b=6, c=1 (3 marks)

    (ii) Show gradient of chord (3 marks)

    (iii) 12+6h+h^2 (2 marks)

    (iv) 12 (1 mark)

    (v) Gradient = 32 +24h+8h^2+h^3

    As h gets close to zero, the gradient becomes ever closer to 32. (3 marks)
    Are you sure you didn't do this in a rush! I think it is a minimum point, bearing was around 118 degrees and distance was 130m? Can you please check these, though I might be wrong as well.
    • 5 followers
    Offline

    ReputationRep:
    (Original post by metaltron)
    Are you sure you didn't do this in a rush! I think it is a minimum point, bearing was around 118 degrees and distance was 130m? Can you please check these, though I might be wrong as well.
    Well I got the Minimum and 130m
    But I think the bearing is right
    90 Degrees + Angle.. Corresponding etc.
    • 0 followers
    Offline

    ReputationRep:
    (Original post by Mr M)
    It's not my property to scan. Under the terms of our agreement with OCR, I may only use past papers with my own students in my Centre.
    Oh right, that's no problem then
    In that case, could I ask how you got the working out for question 4 and question 9 and 11? I suspect I completely stuffed those up, and am wondering how you did it... I remember distinctly looking at the distance question for Q4, and getting 130m as well (I even double-checked!), so a little confused and worried. I also got minimum for question 6, so wondering how you did it
    • Thread Starter
    • 114 followers
    Offline

    ReputationRep:
    (Original post by metaltron)
    Are you sure you didn't do this in a rush! I think it is a minimum point, bearing was around 118 degrees and distance was 130m? Can you please check these, though I might be wrong as well.
    It is a minimum (that is a typo) - I'll change it.

    Bearing is right.
    • 36 followers
    Online

    ReputationRep:
    Hmmn I dont think all of those are right
    • 0 followers
    Offline

    ReputationRep:
    Thank you SO much! But I swear it was minimum point.... :s
    • 4 followers
    Offline

    ReputationRep:
    (Original post by Mr M)
    It is a minimum (that is a typo) - I'll change it.

    Bearing and distance is right.
    Hmm... distance was using formula, s = ut + 0.5 at^2
    Initial velocity and time were both 10. a was 0.6 and t was 10 again.

    So 100 + 30 = 130m?

    Could you please explain the bearing one to me, as I couldn't work out how to get it
    • Thread Starter
    • 114 followers
    Offline

    ReputationRep:
    (Original post by CheeseLord)
    I remember distinctly looking at the distance question for Q4, and getting 130m as well (I even double-checked!), so a little confused and worried.
    My arithmetic error - it is 130m!

    Sorry!!! My excuse is I did do it in 25 mins.
    • 0 followers
    Offline

    ReputationRep:
    Hi Mr M

    I appreciate you uploading the answers however the distance is 130m

    s=(u+v)/2 x t
    s=13x10
    s=130

    you could check this using
    s=ut+0.5at^2
    s=100+30
    s=130
    • 5 followers
    Offline

    ReputationRep:
    (Original post by Mr M)
    My arithmetic error - it is 130m!

    Sorry!!! My excuse is I did do it in 25 mins.
    No Worries! More marks for me eh

    This is great stuff though! I am hoping I have got a half decent mark
    Was the calculus proof for the minimum point re differentiating dy/dx to get d2y/dx2 and putting the number in and as that was > 0 = Minimum?
    • 0 followers
    Offline

    ReputationRep:
    I'm pretty sure it's 130 m :s
    • 2 followers
    Offline

    ReputationRep:
    (Original post by Mr M)
    My arithmetic error - it is 130m!

    Sorry!!! My excuse is I did do it in 25 mins.
    That's a relief.

    Oh well about the bearings :P what is that? One or two marks (You get marks for method) out of 100?
    • Thread Starter
    • 114 followers
    Offline

    ReputationRep:
    (Original post by steviep14)
    No Worries! More marks for me eh

    This is great stuff though! I am hoping I have got a half decent mark
    Was the calculus proof for the minimum point re differentiating dy/dx to get d2y/dx2 and putting the number in and as that was > 0 = Minimum?
    You can do it that way - you would have got a value of 6.
    • 2 followers
    Offline

    ReputationRep:
    Wait so was it a minimum or a maximum?

    Also thank you very much for posting this+posting updates, much appreciated. Your pupils must love you.

Reply

Submit reply

Register

Thanks for posting! You just need to create an account in order to submit the post
  1. this can't be left blank
    that username has been taken, please choose another Forgotten your password?

    this is what you'll be called on TSR

  2. this can't be left blank
    this email is already registered. Forgotten your password?

    never shared and never spammed

  3. this can't be left blank

    6 characters or longer with both numbers and letters is safer

  4. this can't be left empty
    your full birthday is required
  1. By completing the slider below you agree to The Student Room's terms & conditions and site rules

  2. Slide the button to the right to create your account

    Slide to join now Processing…

    You don't slide that way? No problem.

Updated: June 8, 2012
Article updates
Reputation gems:
You get these gems as you gain rep from other members for making good contributions and giving helpful advice.