[0range]

I've done the first part but how would I do part b?

[Zii]

(Original post by 0range)


I've done the first part but how would I do part b?

[0range]

(Original post by Zii)

What would you do from there?

I mean I can get from the form they want it in to x+lnx = 0
would that be sufficient?

[Zii]

(Original post by 0range)
What would you do from there?

I mean I can get from the form they want it in to x+lnx = 0
would that be sufficient?

From what I wrote, I am not sure how you are unable to get the desired result. Add x to 2x. This gives you 3x. Now divide both sides by 3.

[raheem94]

(Original post by 0range)


I've done the first part but how would I do part b?

Zii has already mentioned a method. But another way could have been to convert , then reverse the steps to convert .

[me, myself and I]

x + lnx = 0
x = -lnx
3x = -lnx + 2x
x = (2x - lnx) / 3

[0range]

(Original post by Zii)
From what I wrote, I am not sure how you are unable to get the desired result. Add x to 2x. This gives you 3x. Now divide both sides by 3.

Right sorry heads going a bit blank atm

(Original post by raheem94)
Zii has already mentioned a method. But another way could have been to convert , then reverse the steps to convert .

Yh I think this might be easier thanks

[Zii]

(Original post by raheem94)
Zii has already mentioned a method. But another way could have been to convert , then reverse the steps to convert .

(Original post by 0range)
Yh I think this might be easier thanks

You know, my method is secretly this method in disguise.