[Mr M]

Mr M's OCR (not OCR MEI) M1 Answers May 2012


1. (i) F = 15 N and angle = 61.9 degrees (4 marks)

(ii) E = 17 and angle = 118 degrees (2 marks)


2. (i) v = 3.08 m/s and s = 2.016 m (4 marks)

(ii) 2.669 m (4 marks)


3. (i) 1.6 (2 marks)

(ii) 12.6 m (5 marks)


4. (i) Show coefficient (4 marks)

(ii) 6.02 m/s (6 marks)


5. (i) T = 4.9 N (3 marks)

(ii) 0.49 Ns (5 marks)

(iii) 0.248 m (5 marks)


6. (i) m = 0.500 kg (2 marks)

(ii) H = 10.5 N (2 marks)

(iii) Show coefficient (6 marks)

(iv) Yes (3 marks)


7. (i) 3.1 m/s (3 marks)

(ii) (a) 3.1 (1 mark)

(b) 0.903 m (4 marks)

(c) -1.8 metres per second squared (3 marks)

(iii) 1.415 m/s (4 marks)

[PreciseUrination]

For 4ii), I did the correct method/working but made a calculation error while working the answer. How many marks would I be down?

Thanks for the answers by the way.

[Mr M]

(Original post by PreciseUrination)
For 4ii), I did the correct method/working but made a calculation error while working the answer. How many marks would I be down?

Thanks for the answers by the way.

Hard to say - lose two?

[PreciseUrination]

Cool thanks.

For 5ii) I, and i'm sure many others, forgot to add in the original height of the particle to its total distance. How many would you guess that'd lose me?

Cheers

[wilky94]

For 6 part 3 I used 30 degrees for both angles, but my method was correct. Would I get any marks?


This was posted from The Student Room's iPhone/iPad App

[Tyles]

Thanks for the answers. **** everything about question 1ii. why even ask it again.

[Mr M]

(Original post by PreciseUrination)
Cool thanks.

For 5ii) I, and i'm sure many others, forgot to add in the original height of the particle to its total distance. How many would you guess that'd lose me?

Cheers

I nearly did that too! Lose 1 mark

[Mr M]

(Original post by wilky94)
For 6 part 3 I used 30 degrees for both angles, but my method was correct. Would I get any marks?

Yes you will only be penalised once for that mistake.

[Mr M]

(Original post by Tyles)
Thanks for the answers. **** everything about question 1ii. why even ask it again.

Didn't follow that at all?

[Nathdragon5]

Hi there,

Firstly, thanks for putting up the answers

Secondly, for 5ii) is kgms^-1 fine?

And thirdly, is 0.5kg fine for 6i....

Sorry if these seem like petty queries, I might have done quite well :P

[Mr M]

(Original post by Nathdragon5)
Hi there,

Firstly, thanks for putting up the answers

Secondly, for 5ii) is kgms^-1 fine?

And thirdly, is 0.5kg fine for 6i....

Sorry if these seem like petty queries, I might have done quite well :P

Both fine.

[PreciseUrination]

Yes Kgms^-1 is fine.

Might be [-1], Answers are required to 3s.f unless otherwise specified.

[Nathdragon5]

(Original post by Mr M)
Both fine.

Thanks

[seamen]

how did you find the paper compared to previous years? and I worked out velocity of C at 7iii to be 2.83 but mistakenly used 2.81 for momentum how many marks would I loose, I worked out that 1.41 ms-1 is the velocity after collision.

[Tulian]

Would I lose a mark for stating the momentum equation as m(u-v) but then getting the right answer ?

And for part 2 of 2 , I just done the suvat normally with what they gave. ie u=7 t=0.9 a=-9.8 and so s is 2.331. What would I get out of 4, if anything ?

Thanks.

[Mr M]

(Original post by seamen)
how did you find the paper compared to previous years? and I worked out velocity of C at 7iii to be 2.83 but mistakenly used 2.81 for momentum how many marks would I loose, I worked out that 1.41 ms-1 is the velocity after collision.

Same as usual for difficulty. Probably just lose 1 accuracy mark.

[Fusionary]

Thanks for the answers.

Just to clarify, for Question 6) Part ii) I worked out H as just 6.4sin40 = 4.11 N ( I forgot to add this to the horizontal tension 6.4N to get 10.5N). How many marks would I lose?

[Anon 17]

Can't believe I lost a mark. Sounds arrogant, but I always forget these little things like adding the initial height.

Either way, thanks for the confirmation of the cumulative unofficial mark scheme that's been brewing in the M1 topic.

[Smiley Face :)]

Hi sir, if for q 3 iii I forgot to +1 .. but got 11.6m how many marks do you think I will lose and also 6iii... If I got r = 22.6 and then used my answer to work out Mew to be 0.821... How many marks do you think I will lose?? thanks sir

[Mr M]

(Original post by Tulian)
Would I lose a mark for stating the momentum equation as m(u-v) but then getting the right answer ?

And for part 2 of 2 , I just done the suvat normally with what they gave. ie u=7 t=0.9 a=-9.8 and so s is 2.331. What would I get out of 4, if anything ?

Probably ok for the first question.

1 mark for that part 2 of 2.