[ILovePi]

Does anybody remember what the wording for Q4 was? Specifically part ii?

[Mr M]

(Original post by 4mar_ar5en4l)
Not a massive issue, but shouldn't it be 2.67m (3 s.f.)

No the paper says "give non-exact numerical answers to 3 s.f." - I gave the exact answer instead.

Accuracy greater than 3 s.f. is never penalised anyway.

[the real viper]

(Original post by Mr M)
Hard to say - lose two?

Hi Mr M I think you need to check your answer to the last part of the pulleys question. The answer should be 0.138m

First part before object hits ground

s=0.11025

Then final velocity = 0.735m/s
So initial velocity = 0.735m/s for object going up..

0^2 = 0.735^2 - 2x9.8x s

s= 0.0275625

overall s= 0.1378
therefore 0.138m

[Mr M]

(Original post by McMatty)
Hey,
For Q6iv: i showed it would stay in equilibrium by resolving down the plane using F=ma, came out with negative acceleration, therefore proved it was in equilibrium.
That a correct method or not?!
thanks

Yes that's fine.

[4mar_ar5en4l]

(Original post by Mr M)
No the paper says "give non-exact numerical answers to 3 s.f." - I gave the exact answer instead.

Accuracy greater than 3 s.f. is never penalised anyway.

Oh

[Mr M]

(Original post by the real viper)
Hi Mr M I think you need to check your answer to the last part of the pulleys question. The answer should be 0.138m

First part before object hits ground

s=0.11025

Then final velocity = 0.735m/s
So initial velocity = 0.735m/s for object going up..

0^2 = 0.735^2 - 2x9.8x s

s= 0.0275625

overall s= 0.1378
therefore 0.138m

No you have dropped 1 mark here.

P started 0.11025 m above the ground, rose another 0.11025 m and then finally went up 0.0275 m.

[ILovePi]

(Original post by ILovePi)
Does anybody remember what the wording for Q4 was? Specifically part ii?

Anybody?

[Mr M]

(Original post by ILovePi)
Anybody?

4 (ii) Calculate the speed of the block at the instant the 14 N force was removed.

[Voglie]

(Original post by Mr M)
No you have dropped 1 mark here.

P started 0.11025 m above the ground, rose another 0.11025 m and then finally went up 0.0275 m.

Are you certain that he will drop 1 mark? I did the exact same thing. If you are correct I lost 3 marks max on the paper yayy!!

Not doubting your judgement just want to make sure because I'm ecstatic.

[Tateco]

(Original post by PreciseUrination)
Yes Kgms^-1 is fine.

Might be [-1], Answers are required to 3s.f unless otherwise specified.

They always say or better, you don't get penalised for giving more accurate answers!

[Mr M]

(Original post by Voglie)
Are you certain that he will drop 1 mark? I did the exact same thing. If you are correct I lost 3 marks max on the paper yayy!!

Not doubting your judgement just want to make sure because I'm ecstatic.

Yes. Well done.

[4mar_ar5en4l]

(Original post by ILovePi)
Anybody?

This isn't my paper, but found it on tsr.

[preeyen]

Mr. M please answer my queries

[As_Dust_Dances_]

How many marks would I get if I got 8m and 3.6m for the 2 runners on 3ii) but I subtracted them instead of adding them with the 1m? And also how many marks lost for the very last question as I got v=1.55ms^-1 from getting the left hand side as 3.1 x 0.5 = -0.5v + 1.5v

[hornet_56]

Hi Mr M,
For question 4, I stupidly thought that the block was on a slope rather than the force. For some reason I managed to get the coefficient exactly right but my frictional force was different and therefore the speed required was different but I think I used the right method (finding acceleration etc)
How many marks do you think I will lose and will there be any error carried forward?

Thanks

[Tulian]

Would I get any marks from the 6 mark of the coefficient of friction if my value that I showed was 0.82 ?

[the real viper]

(Original post by Mr M)
No you have dropped 1 mark here.

P started 0.11025 m above the ground, rose another 0.11025 m and then finally went up 0.0275 m.

sneaky, cheers!!!!

[tooambitious]

(Original post by Mr M)
This is a bit vague - lose 2 or 3?

sorry, my phone battery was dying :P.

I resolved perpendicular and parallel.

For paralell i did it correctly

However, for perp rather than 32cos30 - 6.4sin30. i did +6.4.sin30.

After this i did F=muR and found mu (i just gave my answer rather than the show that)

i was wondering how many i would lose for this?

thanks

[tahseen1995]

(Original post by ILovePi)
Does anybody remember what the wording for Q4 was? Specifically part ii?

Scanned paper from today if anyone wants to see actual questions:

Has the answers on there too (which match, thankfully, with Mr M's) which might be useful.

[cantthinkofone]

(Original post by As_Dust_Dances_)
How many marks would I get if I got 8m and 3.6m for the 2 runners on 3ii) but I subtracted them instead of adding them with the 1m? And also how many marks lost for the very last question as I got v=1.55ms^-1 from getting the left hand side as 3.1 x 0.5 = -0.5v + 1.5v

i got 1.55 m/s too do you know what we had to do ?