[KoalaKim]

If i only lost 1 mark then will this be 100 UMS????

[Steve0606]

Does anyone remember the original equation for Q6? I.e. the quadratic equation in x.

[Fusionary]

(Original post by KoalaKim)
If i only lost 1 mark then will this be 100 UMS????

Most likely to be 97 ums.

[linnet18]

Anyone got a list of the questions?

[wasting-time]

argh grumble reckon i got 68/72 because i forgot to divide the quadratic by 5 in one of the questions. Still an A hopefully, although this paper was ridiculusly easy, so the boundaries are probobly gonna be really high.

[tooambitious]

(Original post by Fusionary)
Most likely to be 97 ums.

Seriously doubt that, even jan 12 where 90% was an A 71/72 would be 98 UMS, so in this paper most likely to be 99, and doubtfully could be 100

[Mr M]

(Original post by Mr M (jr))
This is correct and would get full marks.

Mr M is far too quick; some of us still have to teach! (A day of FP2 for me)

I can concur with all his (edited) answers. I would suspect that for Q4 n(n²+1) would get full marks, but can't guarantee it.

I taught all day as well. Did answers and posted them at lunchtime!

You may well be right about Q4.

[Mr M]

(Original post by John2606)
for qs 6 , would you get a error carried forward for part ii?

yes

[Mr M]

(Original post by TehCoolNerd)
Mr M,
I may have been a little bit silly and misread 6ii and thought that they were asking for (1/α -1) and (1/β -1) to be worked out separately. I worked these out to be:
-11/10 +- i root(39)/10

How many marks out of three do you think I would get?
Thanks

They are the right answers to the question you thought you were answering!

Probably drop 2 marks but it might only be 1.

[Mr M]

(Original post by BenjaminKyle)
how many marks in total would i lose for stupidly drawing the loci |z|=|z-8| due to a misread (so that I ended up with a vertical line through (4,0) .... although i did do the circle and shade the right area of the circle correctly) - however i am worried i've made myself lose a lot of marks here as there was more than one part to the question dependent on the loci (such as the intercepts). Ahh i feel so ridiculous, this kind of problem never normally fazes me, i honestly don't know what happened!

You won't be penalised for the same mistake twice. Probably lose two marks in total.

[Mr M]

(Original post by KoalaKim)
If i only lost 1 mark then will this be 100 UMS????

Probably.

[Steve0606]

Mr M what is the quadratic equation given in Q6? The one where you make the u substitution?

[Mr M]

(Original post by Steve0606)
Mr M what is the quadratic equation given in Q6? The one where you make the u substitution?

Didn't I include it in the answers?

[tooambitious]

(Original post by Mr M)
Probably.

Awesome , what is 100 usually? I thought you had to get 72? Well I'm not complaining

[Mr M]

It comes from:





etc

[Steve0606]

Sorry I meant 2x^2 + x + 5 not the one with u, thanks

[Mr M]

(Original post by tooambitious)
Awesome , what is 100 usually? I thought you had to get 72? Well I'm not complaining

It depends on the position of the A and B grade boundaries.

If, for example, 56 raw marks was an A and 49 raw marks was a B, then 100 UMS would be 56 + (2 * (56-49)) = 70.

[tooambitious]

(Original post by Mr M)
It depends on the position of the A and B grade boundaries.

If, for example, 56 raw marks was an A and 49 raw marks was a B, then 100 UMS would be 56 + (2 * (56-49)) = 70.

Oh awesome, I was aware of the formula but go some reason always thought the A an B boundary was often a little further apart so even with a lowish A we need full aw for full UMS. Thanks for clearing that up

[kashkadi]

what do ppl think an A will be?

[bigsam]

Hi, if for a question you simply got an answer and no working, is it possible to get full marks??