Advanced Higher Maths 2012-2013 : Discussion and Help Thread
Discussion for all types of Scottish exams, help on Scottish Results Day and advice on Clearing.
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Advanced Higher Maths 2012-2013 : Discussion and Help ThreadSo, who has taken Maths for next year then ?, I figured it was about the right time to start up a new AH Maths thread for those who have picked it!
Personally, I am quite looking forward to it, had a glance at the Brightred book recently and it looked rather interesting!,
Figured I'd also copy the resources list from the last thread, as it is very useful, Thanks and credit goes to KELZ_26 for compiling these a few years ago in the original thread. If anyone wants anything added to this then just post and I'll edit this list, I'm working on updating certain one's and will add more recent ones as I find them, some of the links don't work as well, so will try and find new versions.
Books:
Selected Books
Maths In Action 1
Maths In Action 2
Maths In Action 3
BrightRed Revision
Practice Papers
Practice Papers
Past Papers
Past Papers:
2001, 2002 and 2003
2004 (original link broken)
2005 (link broken)
2007 - 2011
Marking Instructions:
2001 (link broken)
2002
2003
2004
2005
2006
2007
2008
2009
2010
2011
Other Resources:
LOTS of Practice Questions
SQA AH Maths
Arrangement Documents
HSN Course Summary
Formulae
Notes
Scholar
HSN Forum
Revision Site
Checklist
Teejay
Online scientific calculator
Wolfram Alpha
Integrator
Timings & Outline for Unit 1
Timings & Outline for Unit 2
Timings & Outline for Unit 3
Unit 1 Practice NAB
Unit 2 Practice NAB
Specimen Question Paper with Marking Instructions
Maths Tutorials
More tutorials! -
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Re: Advanced Higher Maths 2012-2013 : Discussion and Help ThreadMeeee(Original post by S119234)
So, who has taken Maths for next year then?
Spoiler:ShowOnly joking, I'm just subscribing
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Re: Advanced Higher Maths 2012-2013 : Discussion and Help ThreadPsh what could be more important than Maths?(Original post by TheFOMaster)
Stupid timetable clash :'( See you Maths, I shall miss you for a year. -
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Re: Advanced Higher Maths 2012-2013 : Discussion and Help ThreadWhat!. Why not try to self-study the subject?(Original post by TheFOMaster)
Stupid timetable clash :'( See you Maths, I shall miss you for a year.
Spoiler:ShowAnd would you require any assistance, you have many past students here on TSR!
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Re: Advanced Higher Maths 2012-2013 : Discussion and Help ThreadHigher English :'( They wouldn't let me self study that.(Original post by mimx)
Psh what could be more important than Maths?
Hmm, I'll ask my Guidance Teacher, she never let me self study English (Saying Int.2 to Higher was too big a jump (LIES)) but maybe she'll let us do AH. Maths. She is a Maths teacher after all :P(Original post by Aerofantastic94)
What!. Why not try to self-study the subject?
Spoiler:ShowAnd would you require any assistance, you have many past students here on TSR! -
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Re: Advanced Higher Maths 2012-2013 : Discussion and Help ThreadIf you don't mind me asking, how well did you perform on your Highers? I mean are you aiming for atleast 3 A/B's. If so then you should defintely take it!(Original post by TheFOMaster)
Hmm, I'll ask my Guidance Teacher, she never let me self study English (Saying Int.2 to Higher was too big a jump (LIES)) but maybe she'll let us do AH. Maths. She is a Maths teacher after all :P
Nevertheless, wish you the best on your inquisition! ha
P.S. Self-studying English would be rediculous tbh.Last edited by Aerofantastic94; 02-06-2012 at 15:28. -
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Re: Advanced Higher Maths 2012-2013 : Discussion and Help ThreadI'll ask :3 I'm aiming for 4A's I think I probably will have completely failed it instead of only moderately failing it if I self studyed it...(Original post by Aerofantastic94)
If you don't mind me asking, how well did you perform on your Highers? I mean are you aiming for atleast 3 A/B's. If so then you should defintely take it!
Nevertheless, wish you the best on your inquisition! ha
P.S. Self-studying English would be rediculous tbh.
To be a teacher If I ever really want to. It's definitely among my top 3 career choices :P(Original post by mimx)
They always say 'its a big jump' from x to y.
Studying English is painful regardless of how you do it. So how come you are?
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Re: Advanced Higher Maths 2012-2013 : Discussion and Help ThreadThen you should have no wooories in supporting the fact you can take it(Original post by TheFOMaster)
I'll ask :3 I'm aiming for 4A's I think I probably will have completely failed it instead of only moderately failing it if I self studyed it...
To be a teacher If I ever really want to. It's definitely among my top 3 career choices :P
Spoiler:ShowBecoming a teacher
...Good luck, if you do become one, haha -
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Re: Advanced Higher Maths 2012-2013 : Discussion and Help ThreadHad a double today. Done a bit of revision and went over the course and done the binomial theorem formulae and revision of long division because apparently it is needed...
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Re: Advanced Higher Maths 2012-2013 : Discussion and Help ThreadDifferent kinds of long division, yes(Original post by JaggySnake95)
Had a double today. Done a bit of revision and went over the course and done the binomial theorem formulae and revision of long division because apparently it is needed...
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Re: Advanced Higher Maths 2012-2013 : Discussion and Help ThreadHow come 2! (2-n)! equals 2?
Also when adding 2 binomial coefficients I know that you add 1 to the top number of both of them and then use the highest number between both of the bottom numbers. So: (excuse poor communication
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(3)----(3)----(4)
(2) + (3) = (3)
But I don't understand how this is shown by the binomial theorem formula 3? -
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Re: Advanced Higher Maths 2012-2013 : Discussion and Help ThreadThis only works if n = 1 or n = 2. If n = 1 then 2!(2 - 1)! = 2! * 1! = 2 * 1 = 2. If n = 2 then you have (2 - 2)! = 0! = 1 and it works similarly.(Original post by JaggySnake95)
How come 2! (2-n)! equals 2?
That is not correct. The correct formula is(Original post by JaggySnake95)
Also when adding 2 binomial coefficients I know that you add 1 to the top number of both of them and then use the highest number between both of the bottom numbers.
, i.e. it only works when the bottom number differs by 1.
![\displaystyle\binom{n}{k - 1} + \displaystyle\binom{n}{k} \\\\
= \dfrac{n!}{\left(k - 1\right)!\left[n - \left(k - 1\right)\right]!} + \dfrac{n!}{k!\left(n - k\right)!} \\\\
= \dfrac{n!k}{k\left(k - 1\right)!\left[\left(n + 1\right) - k\right]!} + \dfrac{n!\left(n + 1 - k\right)}{k!\left(n - k\right)!\left(n + 1 - k\right)}\\\\
= \dfrac{n!k}{k!\left[\left(n + 1\right) - k\right]!} + \dfrac{n!\left(n + 1\right) - n!k}{k!\left[\left(n + 1\right) - k\right]!}\\\\
= \dfrac{n!k + \left(n + 1\right)! - n!k}{k!\left[\left(n + 1\right) - k\right]!}\\\\
= \dfrac{\left(n + 1\right)!}{k!\left[\left(n + 1\right) - k\right]!} = \displaystyle\binom{n+1}{k}](http://www.thestudentroom.co.uk/latexrender/pictures/05/057c81fb8e5e2a54c96e60cae151b9f8.png "\displaystyle\binom{n}{k - 1} + \displaystyle\binom{n}{k} \\\\
= \dfrac{n!}{\left(k - 1\right)!\left[n - \left(k - 1\right)\right]!} + \dfrac{n!}{k!\left(n - k\right)!} \\\\
= \dfrac{n!k}{k\left(k - 1\right)!\left[\left(n + 1\right) - k\right]!} + \dfrac{n!\left(n + 1 - k\right)}{k!\left(n - k\right)!\left(n + 1 - k\right)}\\\\
= \dfrac{n!k}{k!\left[\left(n + 1\right) - k\right]!} + \dfrac{n!\left(n + 1\right) - n!k}{k!\left[\left(n + 1\right) - k\right]!}\\\\
= \dfrac{n!k + \left(n + 1\right)! - n!k}{k!\left[\left(n + 1\right) - k\right]!}\\\\
= \dfrac{\left(n + 1\right)!}{k!\left[\left(n + 1\right) - k\right]!} = \displaystyle\binom{n+1}{k}")
N.B. this proof is the more general form of the answer to 2010 Paper Q5.
Last edited by ukdragon37; 06-06-2012 at 22:37.
