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really simple question

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    • Thread Starter

    whilst working through a C4 paper as part of a question 2(x * 3/x1/2) = 6x1/2

    how is this possible please
    • Thread Starter

    basically that is not clear but the question is asking you to square x + 3/x^1/2 and i can not get all the factors

    (Original post by rsp)
    whilst working through a C4 paper as part of a question 2(x * 3/x1/2) = 6x/x1/2

    how is this possible please
    2 \times \left(x \times \dfrac{3}{x^{\frac{1}{2}}}\right  ) = 2 \times \dfrac{3x}{x^{\frac{1}{2}}} = \dfrac{6x}{x^{\frac{1}{2}}} = (6x)(x^{-\frac{1}{2}}) = 6x^{1-\frac{1}{2}} = 6x^{\frac{1}{2}}

    (Original post by Igrisok)
    If the LHS is 2(x + 3)/(x^0.5), I'm getting x = 3 here. I don't think you have to square anything! Could you link to the question please?
    This isn't an equation to solve. The OP's asking how to get from the LHS to the RHS. Oh and it was x \times 3 not x + 3
    • Thread Starter

    its okay now sorry its not very clear and i managed to work it out

    (Original post by Igrisok)
    Sorry, got a little confused by the second post... But getting from LHS to RHS is pretty simple, OP! It's just 2 * 3 after all :P
    Yeah don't worry so did I, I think the OP was trying to say they had to expand \left( x + \dfrac{3}{x^{\frac{1}{2}}} \right)^2 and were stuck on simplifying that part.

    The OP has since changed her target to 6x^{\frac{1}{2}} - so the indices themselves were the problem, I think.
    • Thread Starter

    (Original post by hassi94)
    2 \times \left(x \times \dfrac{3}{x^{\frac{1}{2}}}\right  ) = 2 \times \dfrac{3x}{x^{\frac{1}{2}}} = \dfrac{6x}{x^{\frac{1}{2}}} = (6x)(x^{-\frac{1}{2}}) = 6x^{1-\frac{1}{2}} = 6x^{\frac{1}{2}}
    thanks that explained it perfect


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