C3-transformation of graphs

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  1. otrivine's Avatar
    • TSR Legend
    • Posts: 14,621
    C3-transformation of graphs
    hi i am getting confused with this reflecting y-axis and x-axis ?
    when would we reflect or not reflect the y or x axis thanks like in modulus/
  2. TenOfThem's Avatar
    • TSR Royalty
    Re: C3-transformation of graphs
    Do you know what modulus does/means
  3. otrivine's Avatar
    • TSR Legend
    • Posts: 14,621
    Re: C3-transformation of graphs
    (Original post by TenOfThem)
    Do you know what modulus does/means
    yes so its like i know how to solve the equations which is one with normally but the other is where you can change the sign
  4. raheem94's Avatar
    • TSR Demigod
    • Posts: 5,512
    Re: C3-transformation of graphs
    (Original post by otrivine)
    yes so its like i know how to solve the equations which is one with normally but the other is where you can change the sign
    You have to look at the graph, see which part intersects with the other line, i.e is it  y = f(x) \ or \ y = - f(x)
  5. otrivine's Avatar
    • TSR Legend
    • Posts: 14,621
    Re: C3-transformation of graphs
    (Original post by raheem94)
    You have to look at the graph, see which part intersects with the other line, i.e is it  y = f(x) \ or \ y = - f(x)
    hi how are you so like when you have the two lines outside and one inside like with x i mean for example |f(x)| and f|x| ?
  6. raheem94's Avatar
    • TSR Demigod
    • Posts: 5,512
    Re: C3-transformation of graphs
    (Original post by otrivine)
    hi how are you so like when you have the two lines outside and one inside like with x i mean for example |f(x)| and f|x| ?
    I am good, what about you?

    I will recommend you to watch some videos relating to this topic, they will be better for your understanding.

    Go to this link.
  7. 99llewellyn99's Avatar
    • Respected Member
    • Posts: 197
    Re: C3-transformation of graphs
    ill reflect the following graph
    Click image for larger version. 

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    if the whole equation is in between the modulus lines like |x3+5x2+3x+2| (not the actual equation but an example) then reflect the part that goes below the x-axis in the x-axis like i have shown below
    Click image for larger version. 

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    if part of theequation is between the modulus lines for example |x3|+5x2+|3x|+2 then draw the graph normally as you would but reflect everything on the right of the y-axis on to the left of the y-axis like below
    Click image for larger version. 

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  8. TenOfThem's Avatar
    • TSR Royalty
    Re: C3-transformation of graphs
    (Original post by 99llewellyn99)

    if part of theequation is between the modulus lines for example |x3|+5x2+|3x|+2 then draw the graph normally as you would but reflect everything on the right of the y-axis on to the left of the y-axis like below
    Click image for larger version. 

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    Are you sure about this response?
  9. raheem94's Avatar
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    • Posts: 5,512
    Re: C3-transformation of graphs
    (Original post by TenOfThem)
    Are you sure about this response?
    It should have been  f(x) = |x|^3 + 5|x|^2 +3|x|+2
    (Original post by 99llewellyn99)
    ill reflect the following graph
    Click image for larger version. 

Name:	IMG_0001.jpg 
Views:	19 
Size:	507.3 KB 
ID:	153378

    if the whole equation is in between the modulus lines like |x3+5x2+3x+2| (not the actual equation but an example) then reflect the part that goes below the x-axis in the x-axis like i have shown below
    Click image for larger version. 

Name:	IMG_0002.jpg 
Views:	19 
Size:	505.9 KB 
ID:	153380

    if part of theequation is between the modulus lines for example |x3|+5x2+|3x|+2 then draw the graph normally as you would but reflect everything on the right of the y-axis on to the left of the y-axis like below
    Click image for larger version. 

Name:	IMG_0003.jpg 
Views:	24 
Size:	509.8 KB 
ID:	153382
    Look above.
  10. 99llewellyn99's Avatar
    • Respected Member
    • Posts: 197
    Definitly been doin it all year and never got it wrong


    This was posted from The Student Room's iPhone/iPad App
  11. TenOfThem's Avatar
    • TSR Royalty
    Re: C3-transformation of graphs
    (Original post by raheem94)
    It should have been  f(x) = |x|^3 + 5|x|^2 +3|x|+2
    Indeed
  12. TenOfThem's Avatar
    • TSR Royalty
    Re: C3-transformation of graphs
    (Original post by 99llewellyn99)
    Definitly been doin it all year and never got it wrong


    This was posted from The Student Room's iPhone/iPad App

    I doubt that

    |x|^3 + x^2 + |x| is not a straightforward transformation of x^3 + x^2 + x

    and

    |x^3| + x^2 + |x| isn't either
  13. 99llewellyn99's Avatar
    • Respected Member
    • Posts: 197
    Oh sorry mut have forgotten about that well I did say tht it wuz not the exact equation wuz jus tryin to say tht thts wht u shld do if part of the equation is between the modulus


    This was posted from The Student Room's iPhone/iPad App
  14. raheem94's Avatar
    • TSR Demigod
    • Posts: 5,512
    Re: C3-transformation of graphs
    (Original post by TenOfThem)
    I doubt that

    |x|^3 + x^2 + |x| is not a straightforward transformation of x^3 + x^2 + x

    and

    |x^3| + x^2 + |x| isn't either
    The correct way to write will be  \ldots |x|^3 \ldots

    But i don't see any difference that will be caused by  |x|^3 \ and \ |x^3| , both will be same.

    Though i even can't understand why he didn't put the modulus sign on the  x^2 .
  15. 99llewellyn99's Avatar
    • Respected Member
    • Posts: 197
    Re: C3-transformation of graphs
    (Original post by raheem94)

    Though i even can't understand why he didn't put the modulus sign on the  x^2 .
    i jus forgot about it
  16. raheem94's Avatar
    • TSR Demigod
    • Posts: 5,512
    Re: C3-transformation of graphs
    (Original post by TenOfThem)
    I doubt that

    |x|^3 + x^2 + |x| is not a straightforward transformation of x^3 + x^2 + x

    and

    |x^3| + x^2 + |x| isn't either
    It is a straightforward transformation.  x^2 will always be positive So even without the modulus sign it should give the graph  f(x) = |x|^3 + |x|^2 + |x|
  17. Basil Brush's Avatar
    • Full Member
    • Posts: 87
    Re: C3-transformation of graphs
    (Original post by 99llewellyn99)
    ill reflect the following graph
    Click image for larger version. 

Name:	IMG_0001.jpg 
Views:	19 
Size:	507.3 KB 
ID:	153378

    if the whole equation is in between the modulus lines like |x3+5x2+3x+2| (not the actual equation but an example) then reflect the part that goes below the x-axis in the x-axis like i have shown below
    Click image for larger version. 

Name:	IMG_0002.jpg 
Views:	19 
Size:	505.9 KB 
ID:	153380

    if part of theequation is between the modulus lines for example |x3|+5x2+|3x|+2 then draw the graph normally as you would but reflect everything on the right of the y-axis on to the left of the y-axis like below
    Click image for larger version. 

Name:	IMG_0003.jpg 
Views:	24 
Size:	509.8 KB 
ID:	153382
    Could you please explain the third one? Why is the left a mirror image of the RHS?
  18. raheem94's Avatar
    • TSR Demigod
    • Posts: 5,512
    Re: C3-transformation of graphs
    (Original post by 99llewellyn99)
    i jus forgot about it
    No worries
  19. 99llewellyn99's Avatar
    • Respected Member
    • Posts: 197
    Re: C3-transformation of graphs
    (Original post by Basil Brush)
    Could you please explain the third one? Why is the left a mirror image of the RHS?
    well its jus a reflection i dont know why it happens but it just does when part of the equation is between modulus lines
  20. raheem94's Avatar
    • TSR Demigod
    • Posts: 5,512
    Re: C3-transformation of graphs
    (Original post by 99llewellyn99)
    well its jus a reflection i dont know why it happens but it just does when part of the equation is between modulus lines
    Modulus makes the value positive.

    So if we have  f(x) = x -2

    At  x = 1 ,  y = 1-2 = -1

    At  x = -1 ,  y = -1-2=-3

    Though if we take the modulus,  f(|x|) = |x| -2

    At  x = 1 ,  y = |1| -2 = -1

    At  x = -1 ,  y = |-1| -2 = 1 -2 = -1

    So both  y values are the same.

    So by taking the modulus, the the negative  x will give the same  y  coordinate as the positive  x value.

    Does it makes sense?
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