[usycool1]

(Original post by ColdKant)
No I completely disagree, march 2012 the gb was 158/200 for an a* and that paper was relatively easy compared to these! if we get a paper like this expect between 145-150/200 for an a* similar to aqa's grade boundaries

Was it actually? I was under the impression (or my teacher told me) that on average, you needed to average about 88% on each paper for an A*.

OK then, I stand corrected

[lubus]

How do you solve question 2 of the sample pdf?

I reckon the newton raphson process is easiest to get a solution, i got 4,25 after 2 iterations (how bored am i?)

everything else looks easy enough. hasnt changed much since i did gcse. some questions are free marks, like the area of the triangle..

[Determined]

(Original post by ColdKant)
yes that is what this post is about and those papers i have attached are how they will be set out

can i please have an attatchment of the March 2012 papers as when i go on the edexcel site its locked

[Alexx53]

(Original post by Belchi)
i need some assistant please lolz, Attachment 154179

the answer is 108 and the mark scheme says

50 : 18 = 25 : 9
Ratio of length = 5 : 3
Ratio of volume = 125 : 27
500 x 27
125

doesn't make sense tho, where did length come from ect

The ratio of the length is 5:3
However, length is measured in just , whereas volume is measure in
This means the ratio has to be cubed to keep it correct when dealing with mass, which is where come from.

A:B is 125:27
So to get from A to B you divide by 125 and multiply by 27, or multiply by

A is 500.

Hope it helps

[ColdKant]

(Original post by Determined)
can i please have an attatchment of the March 2012 papers as when i go on the edexcel site its locked

Ah I am trying my best to get hold of those, I have one paper with some solutions on it. I am a student myself so I don't have direct access to the edexcel site :P
however I have attached the one paper I do have

[Determined]

Thanks so much

[Bigbangtheory010]

(Original post by mia_hilton)
Thank you - i forgot , lets hope i dont do that in the real exam

I don't follow this working out, I understand that both 2n+\-1 will give you an odd but why do square it and - it? An explanation will be much appreciated!

[usycool1]

(Original post by Bigbangtheory010)
I don't follow this working out, I understand that both 2n+\-1 will give you an odd but why do square it and - it? An explanation will be much appreciated!

Because the question says the difference (i.e. minus them) of the square (i.e. square them) of two consecutive odd numbers.

[Belchi]

(Original post by Alexx53)
The ratio of the length is 5:3
However, length is measured in just , whereas volume is measure in
This means the ratio has to be cubed to keep it correct when dealing with mass, which is where come from.

A:B is 125:27
So to get from A to B you divide by 125 and multiply by 27, or multiply by

A is 500.

Hope it helps

oo, i get it, thankyou c:

[Bigbangtheory010]

(Original post by usycool1)
Because the question says the difference (i.e. minus them) of the square (i.e. square them) of two consecutive odd numbers.

Thanks could you help on this question?


14

The line y = 2x + 3 meets the line y = 4x + 2 at the point P.
Find an equation of the line which is perpendicular to the line y = 2x + 3 and which passes through the point P.
(5)
................................ ................................ ..............
(Total for Question 14 = 5 marks)

FYI: you have no graph paper , but the mark scheme mentions it for some reason.

Thanks again
Answer is Y= -0.5X+4.25

[usycool1]

(Original post by Bigbangtheory010)
Thanks could you help on this question?


14

The line y = 2x + 3 meets the line y = 4x + 2 at the point P.
Find an equation of the line which is perpendicular to the line y = 2x + 3 and which passes through the point P.
(5)
................................ ................................ ..............
(Total for Question 14 = 5 marks)

FYI: you have no graph paper , but the mark scheme mentions it for some reason.

Thanks again
Answer is Y= -0.5X+4.25

No problem, and sure

Use simultaneous equations to find the point where the curves intersect (i.e. point P).
Then use the perpendicular gradient rule (=-1) to find the gradient of the perpendicular line.
Substitute the gradient of the perpendicular line and the co-ordinates into either the or formulas (I don't know if they teach the second formula at GCSE or not).

If you still don't understand, see the spoiler below where I have posted a step by step solution to the problem (although try to do it on your own first before looking in the spoiler ).

I don't know why the mark scheme mentions a graph tbh if you had no graph paper

Spoiler:

Show

Use simultaneous equations to find where the lines and intersect. I think the easiest way to do this is to set both equations equal to each other (as they are both y=...):



Now solve this:






Now substitute this into one of the equations to find the y co-ordinate:




So P is:

Now we need to find the gradient of the perpendicular line. The line has a gradient of 2. To find the gradient of the perpendicular line, you use the following equation:

where m is the gradient of the line (in this case, m is 2).

Therefore, the gradient of the perpendicular line is

Now we can substitute these values into :



Then solve the above equation to get that c=4.25

You can then write this as:





Feel free to ask if you don't understand

[InOneDirection]

Can anyone please attach all the papers that are out for the Foundation paper (new spec) it would mean soo much! I'M SOOO TERRIFIED this is a re-take & I was 10 marks off getting a C, and now I just feel like crying, because the spec looks hard!

thanks in advance!

[usycool1]

(Original post by InOneDirection)
Can anyone please attach all the papers that are out for the Foundation paper (new spec) it would mean soo much! I'M SOOO TERRIFIED this is a re-take & I was 10 marks off getting a C, and now I just feel like crying, because the spec looks hard!

thanks in advance!

See here



It may take some time to load, though

[Bigbangtheory010]

(Original post by usycool1)
No problem, and sure

Use simultaneous equations to find the point where the curves intersect (i.e. point P).
Then use the perpendicular gradient rule (=-1) to find the gradient of the perpendicular line.
Substitute the gradient of the perpendicular line and the co-ordinates into either the or formulas (I don't know if they teach the second formula at GCSE or not).

If you still don't understand, see the spoiler below where I have posted a step by step solution to the problem (although try to do it on your own first before looking in the spoiler ).

I don't know why the mark scheme mentions a graph tbh if you had no graph paper

Spoiler:

Show

Use simultaneous equations to find where the lines and intersect. I think the easiest way to do this is to set both equations equal to each other (as they are both y=...):



Now solve this:






Now substitute this into one of the equations to find the y co-ordinate:




So P is:

Now we need to find the gradient of the perpendicular line. The line has a gradient of 2. To find the gradient of the perpendicular line, you use the following equation:

where m is the gradient of the line (in this case, m is 2).

Therefore, the gradient of the perpendicular line is

Now we can substitute these values into :



Then solve the above equation to get that c=4.25

You can then write this as:





Feel free to ask if you don't understand

hi, i understand a lot of apart from when you solve the equation to get 4.25 and to get the gradient do you rearrange the formulae to get 0.5?

thanks

[Bigbangtheory010]

(Original post by usycool1)
No problem, and sure

Use simultaneous equations to find the point where the curves intersect (i.e. point P).
Then use the perpendicular gradient rule (=-1) to find the gradient of the perpendicular line.
Substitute the gradient of the perpendicular line and the co-ordinates into either the or formulas (I don't know if they teach the second formula at GCSE or not).

If you still don't understand, see the spoiler below where I have posted a step by step solution to the problem (although try to do it on your own first before looking in the spoiler ).

I don't know why the mark scheme mentions a graph tbh if you had no graph paper

Spoiler:

Show

Use simultaneous equations to find where the lines and intersect. I think the easiest way to do this is to set both equations equal to each other (as they are both y=...):



Now solve this:






Now substitute this into one of the equations to find the y co-ordinate:




So P is:

Now we need to find the gradient of the perpendicular line. The line has a gradient of 2. To find the gradient of the perpendicular line, you use the following equation:

where m is the gradient of the line (in this case, m is 2).

Therefore, the gradient of the perpendicular line is

Now we can substitute these values into :



Then solve the above equation to get that c=4.25

You can then write this as:





Feel free to ask if you don't understand

is it because x is a half and a half times a half is -o.25 so when you add you get 4.25 you get 4.

[lebron_23]

Apparently, the actual exam won't be as hard as the sample papers that are available. However, i hope they are as they're not overly difficult, and then the grade boundaries will be low.. So more or less guaranteed A*

[gdunne42]

(Original post by InOneDirection)
Can anyone please attach all the papers that are out for the Foundation paper (new spec) it would mean soo much! I'M SOOO TERRIFIED this is a re-take & I was 10 marks off getting a C, and now I just feel like crying, because the spec looks hard!

thanks in advance!

The specification is no harder than the last one, it's just that the style of some of the questions has changed. They have been including some questions in the new style in recent exams anyway. The important message is that you must write down ALL of the steps in your working as well as the answers. In questions that have a * before the question number they will be looking carefully at how clearly you have laid out your solution to the problem and have you stated your answer clearly at the end. They are not looking for an essay, just a well worked out mathematcial solution to a problem with a simple comment that links your answer to the calculations you have done.

The practice papers for it are here:
http://www.colmanweb.co.uk/PastPaper...xcelLinear.htm

Most people think these practice papers are harder than the real exams will be.

[lebron_23]

(Original post by gdunne42)

Most people think these practice papers are harder than the real exams will be.

They WILL be easier than the practice papers. I was speaking to someone who went to the exam board meeting and they said that the practice papers were slightly harder than what the exam was going to be. So i would get too down about it. Although i hope the papers are hard (they're still do-able) so the grade boundaries will be low and then an A* is more or less guaranteed

[usycool1]

(Original post by Bigbangtheory010)
hi, i understand a lot of apart from when you solve the equation to get 4.25 and to get the gradient do you rearrange the formulae to get 0.5?

thanks

You've already got the gradient when you do:

(Original post by Bigbangtheory010)
is it because x is a half and a half times a half is -o.25 so when you add you get 4.25 you get 4.

Yup:

[Bigbangtheory010]

(Original post by usycool1)
You've already got the gradient when you do:







Yup:

thanks, just have to remember the -1/m for the exam!