[hilaire]

Hey

I was just marking a practice paper for Physics, and I was trying to calculate the UMS mark to see if I had received 90%. I was wondering if anyone could tell me how accurate this method is?

I have the guide from the OCR website which tells you to divide the UMS marks in the boundary by the raw marks in the boundary and multiply by the amount of raw marks that you gained into that boundary (this is the amount of UMS into the grade). So for the June 2011 paper conversion factor = 30/36 (you needed 64/100 for an a) = 5/6

However, I was reading the examiner's report and they said that the top mark that anyone got for that exam was 93. So 29*(5/6)=~24
120+24 = 144 - so that means nobody got full ums in that paper, even though they got the best mark in the country?
So basically, I was wondering whether this method still works for calculating the top end of marks.
Thanks if you can help, and sorry if this isn't clear

[Unkempt_One]

The top UMS band is decided by doubling the gap in raw marks between the A and B grade boundaries, and then adding this to the A boundary. So if on the example you gave, a B was 65 and an A was 73, full UMS would be 89.

[117r]

So, let's say the B boundary was 52/100 (just a guess, you can look this up later)
We already know the A boundary is 64/100

So, if you get, say, 58/100, you are 6 marks above the B boundary.
The gap between A and B in this case is 12 raw marks. You are 6/12 of the way into a B as it were.
The gap between A and B in UMS is always 10%. You were 6/12 of the way into a B, so you were 5% over a B in UMS, hence your UMS mark is 75%.

100 UMS is calculated by doubling the distance between the A boundary and the B boundary and adding it onto the A boundary.
So, taking our boundaries that I just made up, since the difference between A and B is 12, you double that and add it onto A. 64+(12*2)=88
Therefore the person who got 93 raw marks would have made it over 100 UMS, and 100 UMS would be what he received.

One last example then. If you got 70/100 raw marks, you were 6 marks into an A. The difference between an A and full UMS we have established is 12*2=24.
Hence you are 6/24 of the way above and A. The difference between an A and full UMS is always 20%. 6/24*20=5. Add 5 onto 80, and so 85% is your UMS mark in this case.

Hope that helped a little, ask if it made no sense!!

[myyrh]

Just use this.
http://www.thestudentroom.co.uk/atta...0&d=1201801820

[hilaire]

Aaaah I completely didn't know that, thank you so much everyone!

So if 100% UMS is 88/100, 90% UMS would be 76/100? I got 78/100 on this paper so does that mean I would have got 90%?
Sorry if I'm being really dense right now! Exam stress is getting to me I think!!