I've done part a)
part b) I subbed the values into the tangent and got the values of t as 4 and -1, which are correct. However I was unsure of what to do here so I looked at the solutions and they subbed the values of t into the point P, and i'm not sure why, Is it because P has the parametric equations? as in x = at^2 and y = 2at? So P is just a general point on the parabola? If not then why into P?
(Original post by lemonpwns1)
So P is just a general point on the parabola?
thanks for the quick response
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