Need some help guys
The parametric equations of a curve are x=2t^2 and y=4t. Two points on the curve are P(2p^2,4p) and Q(2q^2,4q)
Show that the gradient of the chord joining the points P and Q is 2/(p+q)
So i tried by finding the gradient by using y step over x step and i did not get anything like 2/(p+q)
This is a 2 mark question, so it must be something simple:/
BTW this is part B of the question
part a was .. show that the gradient of the normal to the curve at P is -P (I got that right)..
Once you have your expression, factorise (difference of two squares)
Your method is correct, what did you do. Post your working so we can find the mistake. Remember that x^2-y^2=(x+y)(x-y)
you know the gradient is: [4p-4q]/[2p^2-2q^2] = [4(p-q)]/2(p+q)(p-q)]
Thanks for posting! You just need to create an account in order to submit the post
Already a member?
Oops, something wasn't right
please check the following:
Not got an account?
Sign up now
You get these gems as you gain rep from other members for making good contributions and giving helpful advice.