Questions from aqa jun 10 Chem 4- Please help!

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  1. popnit's Avatar
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    Questions from aqa jun 10 Chem 4- Please help!
    I've attached the paper and MS for Jun 10 chem 4 and I was wondering if anyone could help me on some qs.

    - Qs 3e (i) & (ii)
    - Qs 4b
    - 8a

    Please could someone explain these to me. Thanks in advance!
    Attached Files
  2. File Type: pdf AQA-CHEM4-W-QP-JUN10.pdf (115.5 KB, 106 views)
  3. File Type: pdf AQA-CHEM4-W-MS-JUN10.pdf (576.3 KB, 156 views)
  4. Last edited by popnit; 07-06-2012 at 21:07.
  5. popnit's Avatar
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    Anyone please!!!

    This was posted from The Student Room's Android App on my HTC Wildfire
  6. wenger16's Avatar
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    Re: Questions from aqa jun 10 Chem 4- Please help!
    8a) Friedal Crafts acylation - electrophilic substituion reaction.

    so you know to get electrophile reaction is:

    RCOCL + ALCL3 --) RCO3+ + ALCL4-

    And so one of the answers is alcl3

    and now just look at product given in question to work out what the other is..

    as it is benzene--c=0--ch2ch3 thats product given so from that you know ch3ch2c=0cl must have been added.

    so overalll reaction to get electrophile:

    ch3ch2c=0cl + alcl3 -) ch3ch2c0+ + alcl4-

    ch3ch2c0+ is electrophile its used in electrophile substitution which is next q..
    Last edited by wenger16; 08-06-2012 at 07:40.
  7. wenger16's Avatar
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    Re: Questions from aqa jun 10 Chem 4- Please help!
    4b im not sure need to revise that again.

    3e)

    Its primary amine so its gonna be

    R-N-H2

    And because its carbon nmr focus on carbons.

    There are 3 peaks so 3 different carbons in 3 different environments.

    So theres ch2 - thats 1 environment

    c conected to 2 ch3's is another environment as its all same environment as you cant tell which is which so same enviroment.

    and other ch3 is 3rd carbon different enviroment so thats 3rd peak...

    so:

    NH2--CH2--C(CH3)2--CH3


    3bii)

    Tertiary amines are like this:

    N-R3 connected to 3 r groups.

    Theres a doublet so yy=ou know because of n+1 rule there has to be a carbon in there connected to only 1 H.

    Also N has to be connected to 3 r groups but if its connected to only 1 carbon then no adjacent hydrogen for that particular carbon so no peak.

    So its:

    CH3-N-CH3 NO PEAKS GIVEN FROM THIS

    AND THEN OTHER PART CONNECTED TO N IS :

    CH3-CH-CH3

    CH GIVES THE DOUBLET, 3 SETS OF HYDROGENS GIVE 3 PEAKS.
  8. wenger16's Avatar
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    Re: Questions from aqa jun 10 Chem 4- Please help!
    Btw can i ask you?

    theres jan 10/ june 10/ jan 11/ june 11/ jan 12 papers

    and spec papers and old papers...are there any other papers for aqa exam board?
  9. popnit's Avatar
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    Thanks so much everyone.
    And to answer your qs ^^^ I think if you search around you'll find papers all the way back from 2003 but they're a slightly different syllabus/spec

    This was posted from The Student Room's Android App on my HTC Wildfire
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