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C2 - Sum of series.. Need guidance!

Alright, so I can't use LaTex on this yet so I'll try type this the best I can.

I have a question, it says that the formula for the nth term is 12(0.5)^n -3. Then, it gives in sigma notation, show that the sum of the terms from 1 to 20 is -48. Could someone show me how to find the sum of this? I'm having a mind blank.
Reply 1
You can split the summation into two:

n=120(12(0.5)n3)=n=12012(0.5)nn=1203\displaystyle \sum_{n=1}^{20} \left(12(0.5)^n - 3\right) = \sum_{n=1}^{20} 12(0.5)^n - \sum_{n=1}^{20} 3

Does that help you?
(edited 11 years ago)
Reply 2
Original post by notnek
You can split the summation into two:

n=120(12(0.5)n3)=n=12012(0.5)nn=1203\displaystyle \sum_{n=1}^{20} \left(12(0.5)^n - 3\right) = \sum_{n=1}^{20} 12(0.5)^n - \sum_{n=1}^{20} 3

Does that help you?


Yes I figured that out after a few attempts haha, thanks!

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