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Kc Question troubles!

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    Here's the q:

    N2O4 and NO2 coexist in this equilibrium..

    2 NO2 <--=--> N2O4

    A chemist adds 4.00mol no2 to a container with a volume of 2dm3. The container is sealed, heated to a constant temp and allowed to reach equilibrium.

    the equilibrium mixture contains 3.2mol no2. Calculate Kc under these conditions.

    I understand everything up to the point where reacting ratio is 2:1 and that concentration of no2 is 1.6mol dm3. So I thought that the conc. of N2O4 would be 0.8, but markscheme says its 0.2. Why is this??
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    0.8 mol of NO2 has reacted, which means 0.4 mol of N2O4 is present according to the ratio in the chemical equation. Convert moles into concentration and it should be obvious :yes:

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