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# Gcse maths question (triangles) help needed Tweet

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1. Gcse maths question (triangles) help needed

So I need some help answering that question
I know that both triangles have a right angle, and share side PC, but I need one more reason..
2. Re: Gcse maths question (triangles) help needed
They both share BC.
3. Re: Gcse maths question (triangles) help needed
Angle PCB = 90 - Angle PCA = Angle CAP
4. Re: Gcse maths question (triangles) help needed
(Original post by aa05)

So I need some help answering that question
I know that both triangles have a right angle, and share side PC, but I need one more reason..
APC=90=BPC because there is 180 degrees along a straight line.

Due to there being 180 degrees in a triangle, the remaining angles of each triangle must add up to 180.
... So PAC+ACP=90 and PBC+BCP=90

If CP bisects the right angle C, it divides 90 degrees into two groups. E.g. 80 degrees and 10 degrees (one group belonging to each triangle). This means the remaining third angle of each triangle becomes the remainder (or the other group).

Hope that makes sense, that's how I would say it.
5. Re: Gcse maths question (triangles) help needed
Or if you want something fancier you could let the
angle PAC=x
then angle ACP=90-x,
then angle BCP=90-90-(-x)=x,
then angle CBP=90-x.

Therefore both triangles have the same angles- x,90-x and 90 for 0<x<90
6. Re: Gcse maths question (triangles) help needed
thanks all of you