Gcse maths question (triangles) help needed

Maths and statistics discussion, revision, exam and homework help.

Announcements Posted on
Please change your TSR password 23-05-2013
Enter our travel-writing competition for the chance to win a Nikon 1 J3 camera 20-05-2013
IMPORTANT: You must wait until midnight (morning exams)/4.30AM (afternoon exams) to discuss Edexcel exams and until 1pm/6pm the following day for STEP and IB exams. Please read before posting, including for rules for practical and oral exams. 28-04-2013
Sign in to Reply
  1. aa05's Avatar
    • Junior Member
    • Posts: 46
    Gcse maths question (triangles) help needed
    Click image for larger version. 

Name:	17.png 
Views:	62 
Size:	27.5 KB 
ID:	155197
    So I need some help answering that question
    I know that both triangles have a right angle, and share side PC, but I need one more reason..
    Thanks in advance to anyone who answers
  2. Dualcore's Avatar
    • Respected Member
    • Posts: 188
    Re: Gcse maths question (triangles) help needed
    They both share BC.
  3. electriic_ink's Avatar
    • TSR Demigod
    • Location: London
    • Posts: 5,639
    Re: Gcse maths question (triangles) help needed
    Angle PCB = 90 - Angle PCA = Angle CAP
  4. lou_100's Avatar
    • Benevolent Member
    • Posts: 813
    Re: Gcse maths question (triangles) help needed
    (Original post by aa05)
    Click image for larger version. 

Name:	17.png 
Views:	62 
Size:	27.5 KB 
ID:	155197
    So I need some help answering that question
    I know that both triangles have a right angle, and share side PC, but I need one more reason..
    Thanks in advance to anyone who answers
    APC=90=BPC because there is 180 degrees along a straight line.

    Due to there being 180 degrees in a triangle, the remaining angles of each triangle must add up to 180.
    ... So PAC+ACP=90 and PBC+BCP=90

    If CP bisects the right angle C, it divides 90 degrees into two groups. E.g. 80 degrees and 10 degrees (one group belonging to each triangle). This means the remaining third angle of each triangle becomes the remainder (or the other group).

    Hope that makes sense, that's how I would say it.
  5. Dualcore's Avatar
    • Respected Member
    • Posts: 188
    Re: Gcse maths question (triangles) help needed
    Or if you want something fancier you could let the
    angle PAC=x
    then angle ACP=90-x,
    then angle BCP=90-90-(-x)=x,
    then angle CBP=90-x.

    Therefore both triangles have the same angles- x,90-x and 90 for 0<x<90
  6. aa05's Avatar
    • Junior Member
    • Posts: 46
    Re: Gcse maths question (triangles) help needed
    thanks all of you
Sign in to Reply
Share this discussion:  
Article updates
Moderators

We have a brilliant team of more than 60 volunteers looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

Reputation gems:
The Reputation gems seen here indicate how well reputed the user is, red gem indicate negative reputation and green indicates a good rep.
Post rating score:
These scores show if a post has been positively or negatively rated by our members.