A2 Physics Question Magnetic Fields ( yes i know this is maths board)

Hey can anyone help me. Im putting this on here cause the physics forum is empty and i presume many here do physics aswell.

A 200 turn coil of cross sectional area 4.2 x 10 ^-4 m sq is situated in a changing magnetic field. The flux density changes according to the graph.

a) Determine the flux linkage at time t=5ms.
b) estimate the rate of change of flux linkage at time t=5ms.
c) State the emf induced in the coil.

Reading of graph that gradient at 5ms is 12.5 and B (flux density) is 0.12 Teslas at 5ms if this helps?

Thanks to a genius that solves it for me

Reply 1

yusufu

16

I should know since we've been doing magnetic fields for the past two months. but I don't :redface:

Reply 2

Wkd_Intent

I cant help with a) or b) without the graph sorry.
But C) no problem
Using Flux (Wb) = Flux density (T) x Area (m^2) [ Ф= BA]
Using your values, 0.12 T x 4.2 x10 ^ -4 m^2 = 0.0000504 Wb (check working)

Now using Induced EMF (V) = (Number of turns x delta &#1060 :wink:

/ delta time (sec) [EMF=(N&#1060 :wink:

/t]

So (200 turns x 0.0000504 Wb) / 5 x 10^-3 = 2.016Volts

The time you gave was milliseconds right? Either way you better recalculate it but it must be converted to seconds.

Reply 3

yusufu

16

Wkd_Intent

I cant help with a) or b) without the graph sorry.
But C) no problem
Using Flux (Wb) = Flux density (T) x Area (m^2) [ Ф= BA]
Using your values, 0.12 T x 4.2 x10 ^ -4 m^2 = 0.0000504 Wb (check working)

Now using Induced EMF (V) = (Number of turns x delta &#1060 :wink:

/ delta time (sec) [EMF=(N&#1060 :wink:

/t]

So (200 turns x 0.0000504 Wb) / 5 x 10^-3 = 2.016Volts

The time you gave was milliseconds right? Either way you better recalculate it but it must be converted to seconds.

ah... this seems familiar. :smile:

A2 Physics Question Magnetic Fields ( yes i know this is maths board)

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