Angles
Maths and statistics discussion, revision, exam and homework help.
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AnglesHow would I prove this.
Angles.bmp -
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Re: AnglesLook at shape its "S" angles.
so STQ = TQR
Therefore TQU = 100-X
As it is an isoceles triangle as 2 sides are same so the adjacent angle QUT is also 100-X
Therefore to find angle QTU we do:
Sum of angles in triangle = 180 degrees
=180-(100-x)+(100-x)
=180-(200-2x)
=-20-2x
=(2x-20)degrees -
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Re: AnglesPlease don't post full solutions.(Original post by wenger16)
Look at shape its "S" angles.
so STQ = TQR
Therefore TQU = 100-X
As it is an isoceles triangle as 2 sides are same so the adjacent angle QUT is also 100-X
Therefore to find angle QTU we do:
Sum of angles in triangle = 180 degrees
=180-(100-x)+(100-x)
=180-(200-2x)
=-20-2x
=(2x-20)degrees
It is one of the rules of this forum not to post solutions. Plus in this case it's much more beneficial for the OP to work through the problem himself considering his exam is coming up very soon. -
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Re: AnglesHow do you get from -2x to 2x(Original post by wenger16)
Look at shape its "S" angles.
so STQ = TQR
Therefore TQU = 100-X
As it is an isoceles triangle as 2 sides are same so the adjacent angle QUT is also 100-X
Therefore to find angle QTU we do:
Sum of angles in triangle = 180 degrees
=180-(100-x)+(100-x)
=180-(200-2x)
=-20-2x
=(2x-20)degrees -
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Re: AnglesIts equal you can always reverse signs.(Original post by zed963)
How do you get from -2x to 2x
or think of it as multiplying whole thing by -1.
ye its z angle so you know its 100-x -
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Re: AnglesThanks for that.(Original post by wenger16)
Its equal you can always reverse signs.
or think of it as multiplying whole thing by -1.
ye its z angle so you know its 100-x
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Re: AnglesHope my bank doesn't agree.(Original post by wenger16)
Its equal you can always reverse signs.
Actually you made a mistake multiplying out the bracket.
180-(200-2x) = 180-200 + 2x = -20 + 2x
