[Candit]

The Curve y= (10/2x+1) -2 intersects the x-axis at A, The tangent to the curve at A intersects the y-axis at C.

i) Show that the equation of AC is 5y + 4x = 8
ii) Find the distance AC

do i differentiate it twice?

[notnek]

Have you found the point A? Have you found the equation of the tangent?

You need to say where you're up to in the question or I can only guess why you're stuck.

[Candit]

i just differentiate y and got stuck there

[raheem94]

(Original post by Candit)
The Curve y= (10/2x+1) -2 intersects the x-axis at A, The tangent to the curve at A intersects the y-axis at C.

i) Show that the equation of AC is 5y + 4x = 8
ii) Find the distance AC

do i differentiate it twice?

The equation you have written is ambiguous.

Do you mean

[Candit]

yes

[raheem94]

(Original post by Candit)
The Curve y= (10/2x+1) -2 intersects the x-axis at A, The tangent to the curve at A intersects the y-axis at C.

i) Show that the equation of AC is 5y + 4x = 8
ii) Find the distance AC

do i differentiate it twice?

Part (a),

Set y=0, to find the x-coordinate of A.
Differentiate y = 10/(2x+1) -2 and sub in the x-coordinate of A, to get the gradient at A.
Use the coordinates of A and the gradient obtained to find the equation of tangent at A.
Set x=0 in the equation of tangent at A, to find the y-coordinate of point C.

Now find the gradient of AC, by using , then form an equation.

[Candit]

umm ok get it thanks alot