Integrating 1/(1-Cos4x)

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  1. sabre2th1's Avatar
    1 11-06-2012  15:04
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    Integrating 1/(1-Cos4x)
    How would you go about integrating? 1/(1-Cos4x)..
  2. SParm's Avatar
    2 11-06-2012  15:06
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    Re: Integrating 1/(1-Cos4x)
    (Original post by sabre2th1)
    How would you go about integrating? 1/(1-Cos4x)..
    Can you think of what 1 - cos (4x) might equal in terms of sin (2x)? (Hint hint: double angle formulae will be useful here.)
  3. sabre2th1's Avatar
    3 11-06-2012  16:00
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    Re: Integrating 1/(1-Cos4x)
    (Original post by SParm)
    Can you think of what 1 - cos (4x) might equal in terms of sin (2x)? (Hint hint: double angle formulae will be useful here.)
    Cos (4x) = 1-2Sin2(2x)

    how do I progress from here?

    thanks
  4. raheem94's Avatar
    4 11-06-2012  16:03
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    Re: Integrating 1/(1-Cos4x)
    (Original post by sabre2th1)
    Cos (4x) = 1-2Sin2(2x)

    how do I progress from here?

    thanks
    1 - \cos (4x) = 1 - (1- 2 \sin^2(2x) ) = 2 \sin^2(2x)

    Remember, \dfrac{1}{\sin^2x} = cosec^2(x)
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  5. sabre2th1's Avatar
    5 11-06-2012  16:59
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    Re: Integrating 1/(1-Cos4x)
    (Original post by raheem94)
    1 - \cos (4x) = 1 - (1- 2 \sin^2(2x) ) = 2 \sin^2(2x)

    Remember, \dfrac{1}{\sin^2x} = cosec^2(x)
    Oh! Thanks a lot
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