(Original post by Yosemite80)
for 4 if nobody has this
not sure about a but i said something about conservation of momentum
I said as the alpha particle approaches the gold atom it decelerates losing kinetic energy , and gold nuclei gains kinetic energy due to the loss of kinetic energy of the alpha particle, therefore it accelerates. I think i'm missing a point or too.
b should be lines curving away from the opposite particle with arrows aiming away from each other i think?
I drew a graph on this forum see if it's similar
c use F=Qq/4(pi)E0r^2 with Q as 79*1.6*10^-19 and q as 2*10^-19, substitute r and get about 10N
d 1/r^2 graph, for safety precautions it should pass through (12,2.5) as well as the X i think, but i didnt extend it beyond the X, so not sure if it would get both marks
Did inverse square law but not through that point. How did you calculate that point?
and 5 if nobody has beaten me to it
a - neutrons = 234-92=142
bii - speed=sqr(2KE/m) with mass substituted and KE from prev q
c - each nuclei generated 5.6MeV or 9*10^-13J so divide power by that to get initial activity
cii - half life * lambda = ln2 so rearrange for lambda, half life = 88*3.16*10^7, lambda should be 2.49*10^-10
ciii - rearrange A=N(lambda) and N is 2.81*10^23
ciii2 - divide N by avogadro constant and multiply by molar mass (0.24*(2.81*10^23/6.02*10^23)) to get 0.111-0.112kg
I got different i thought the molar mass was 0.24kg then I multiplied by the relative atomic mass of 238 to get 57.12kg
6a the neutrons released in the decay can be absorbed by more uranium nuclei
b - not sure how well i did on this one so i wont risk putting it on here