[Dr Ben]

here my code:

#include <stdio.h>
#include <limits.h>
#include <float.h>

int main()
{
    //chars
    int maxUChar, maxSChar, minSChar;

    maxSChar = SCHAR_MAX;
    minSChar = SCHAR_MIN;
    maxUChar = UCHAR_MAX;

    printf("The range of a schar is: %d <= x <= %d\n", minSChar, maxSChar);
    printf("The range of a uchar is: 0 <= x <= %d\n", maxUChar);
    printf("\n");

    //ints
    int maxUInt, maxSInt, minSInt;

    maxUInt = UINT_MAX;
    maxSInt = INT_MAX;
    minSInt = INT_MIN;

    printf("The range of an int is: %d <= x <= %d\n", minSInt, maxSInt);
    printf("The range of a uint is: 0 <= x <= %d\n", maxUInt);


}

here's my output:

the last line (that reads "printf("The range of a uint is: 0 <= x <= %d\n", maxUInt);") appears to print out "The range of uint is: 0 <= x <= -1".

Why does it say -1? According to the O'Reilly C Programming Language book it should say 65536 instead of -1

[JGR]

int hasn't been 16 bits wide since the DOS era.

If you want to print an unsigned int, use the %u format code.
You'll most likely get a result of 4294967295.

If you absolutely must have 16 bit wide integers, use a short (and the associated format code).

[Dr Ben]

(Original post by JGR)
int hasn't been 16 bits wide since the DOS era.

If you want to print an unsigned int, use the %u format code.
You'll most likely get a result of 4294967295.

If you absolutely must have 16 bit wide integers, use a short (and the associated format code).

ah ok thanks, but do you know why its saying -1? the constants USHORT_MAX, and ULONG_MAX also appear to have the values of -1

[JGR]

(Original post by Dr Ben)
ah ok thanks, but do you know why its saying -1? the constants USHORT_MAX, and ULONG_MAX also appear to have the values of -1

Have a read of this http://en.wikipedia.org/wiki/2s_compliment
It explains how signed integers work.