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# FP3 Help Pease, Exam In 2 Days And I Self Teach !!!!! Tweet

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1. FP3 Help Pease, Exam In 2 Days And I Self Teach !!!!!
Please have a look at Q8B here
QP: http://store.aqa.org.uk/qual/gce/pdf...W-QP-JAN10.PDF
MS: http://store.aqa.org.uk/qual/gceasa/...W-MS-JAN10.PDF

And I just have two questions which follow in the attachment in the following post
Last edited by member910132; 12-06-2012 at 11:45.
2. Here

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Attached Thumbnails

3. Re: FP3 Help Pease, Exam In 2 Days And I Self Teach !!!!!
The 2) the first sketch youve made is the area that would be calculated.

For 1) you want to find the area of the triangle OPQ, by knowing the pole length of P and Q and the length of PQ.

Good luck on Thursday! Are you sitting C4 as well?
4. Re: FP3 Help Pease, Exam In 2 Days And I Self Teach !!!!!
Work out the area of triangle OPQ.

Subtract form that area 2 x integral from pi/6 to pi/2 of whatever it is you have to integrate.
5. Re: FP3 Help Pease, Exam In 2 Days And I Self Teach !!!!!
(Original post by HouseStark)
The 2) the first sketch youve made is the area that would be calculated.

For 1) you want to find the area of the triangle OPQ, by knowing the pole length of P and Q and the length of PQ.

Good luck on Thursday! Are you sitting C4 as well?

(Original post by BabyMaths)
Work out the area of triangle OPQ.

Subtract form that area 2 x integral from pi/6 to pi/2 of whatever it is you have to integrate.
Thnx, I know how to do it now but I am asking a general question, can anyone answer q1 on my attachment ? How would I find that area ?

Nah no c4, just fp3.
6. Re: FP3 Help Pease, Exam In 2 Days And I Self Teach !!!!!
(Original post by member910132)
How would I find that area ?
That's just triangle OPA + the integral. You know AP=1. You know r=2. Angle OPA is pi/2 - pi/6= pi/3.

Area of triangle = 1/2 x 1 x 2 x sin(pi/3).

I'm afraid that's without referring back to the diagram so I could have some details wrong.