Vector eqn of a line - what way?

Maths and statistics discussion, revision, exam and homework help.

Announcements Posted on
TSR launches Learn Together! - Our new subscription to help improve your learning 16-05-2013
IMPORTANT: You must wait until midnight (morning exams)/4.30AM (afternoon exams) to discuss Edexcel exams and until 1pm/6pm the following day for STEP and IB exams. Please read before posting, including for rules for practical and oral exams. 28-04-2013
Sign in to Reply
  1. acomber's Avatar
    • Full Member
    • Posts: 120
    Vector eqn of a line - what way?
    If I have a vector equation of a line eg

    \begin{pmatrix} x \\ y \end{pmatrix} = \begin{pmatrix} 1 \\ 2 \end{pmatrix} + \lambda  \begin{pmatrix} 1 \\ 1 \end{pmatrix}

    Then I can see the direction is (1,1) ie at 45 degree angle. And I can easily visualise this line in my mind.

    If there were a point A and a point B on the line then the vector AB would be different to the vector BA. Is there a concept of the way line is going - the sort of arrow of the line? Or is it just seen as a line which goes in both directions into infinity and there is no concept of 'what way'? Just wondering?
  2. BabyMaths's Avatar
    • Peer Of The TSR Realm
    • Posts: 1,553
    Re: Vector eqn of a line - what way?
    You can consider the direction as lambda increases or as lambda decreases if you like.
  3. acomber's Avatar
    • Full Member
    • Posts: 120
    Re: Vector eqn of a line - what way?
    (Original post by BabyMaths)
    You can consider the direction as lambda increases or as lambda decreases if you like.
    Not quite sure I understand. Are you suggesting positive lambda is one way, -ve the other?
  4. BabyMaths's Avatar
    • Peer Of The TSR Realm
    • Posts: 1,553
    Re: Vector eqn of a line - what way?
    (Original post by acomber)
    Not quite sure I understand. Are you suggesting positive lambda is one way, -ve the other?
    Not positive and negative but rather, increasing and decreasing.
  5. mikelbird's Avatar
    • Respected Member
    • Location: Gloucestershire
    • Posts: 187
    Re: Vector eqn of a line - what way?
    (Original post by acomber)
    If I have a vector equation of a line eg

    \begin{pmatrix} x \\ y \end{pmatrix} = \begin{pmatrix} 1 \\ 2 \end{pmatrix} + \lambda  \begin{pmatrix} 1 \\ 1 \end{pmatrix}

    Then I can see the direction is (1,1) ie at 45 degree angle. And I can easily visualise this line in my mind.

    If there were a point A and a point B on the line then the vector AB would be different to the vector BA. Is there a concept of the way line is going - the sort of arrow of the line? Or is it just seen as a line which goes in both directions into infinity and there is no concept of 'what way'? Just wondering?
    The displacement vector you give certainly has a direction, namely a combination of 1 unit in the positive x direction and one unit in the positive y direction. However the line itself has no sense of direction...it simply depends on whether the lambda is positive or negative to give a particular point on the line. So if the lambda is positive then you are going to travel from the given point on the line in the same direction as the displacement vector and if lambda is negative then you are going to travel in the opposite direction to that given by the displacement vector. So...the displacement vector has a direction and the line is just a line extending to infinity in either direction.
Sign in to Reply
Share this discussion:  
Article updates
Moderators

We have a brilliant team of more than 60 volunteers looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

Reputation gems:
The Reputation gems seen here indicate how well reputed the user is, red gem indicate negative reputation and green indicates a good rep.
Post rating score:
These scores show if a post has been positively or negatively rated by our members.