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    pleaseeeeeeeeee can anyone solve this for me plzzzzzzzzzzz


    In this question, give all values of pH to two decimal places.
    Calculating the pH of aqueous solutions can involve the use of equilibrium constants
    such as Kw and Ka
    Kw is the ionic product of water. The value of Kw is 5.48 × 10
    –14
    mol
    2
    dm
    –6
    at 50 °C
    Calculate the pH of pure water at 50°C
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    (Original post by moniasajid)
    pleaseeeeeeeeee can anyone solve this for me plzzzzzzzzzzz


    In this question, give all values of pH to two decimal places.
    Calculating the pH of aqueous solutions can involve the use of equilibrium constants
    such as Kw and Ka
    Kw is the ionic product of water. The value of Kw is 5.48 × 10
    –14
    mol
    2
    dm
    –6
    at 50 °C
    Calculate the pH of pure water at 50°C
    Post in chemistry section and make the format clearer as i don't have a clue what it is meant to say.
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    kw = [H+]+[OH-]
    kw= [H+]^2 (squared)- because pure water dissociates into equal amounts of h+ and oh-

    then use pH= -log(H+)

    Input values and you should get an answer

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Updated: June 12, 2012
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