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# C4: Integration Tweet

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1. C4: Integration

Where the limits are 1 and 0 (I don't know how to put that in to the format above haha)
Giving you answer in the form pln3 +qln2 +r where p,q and r are integers.

The answer is 37ln3 - 36ln2 - 14.

Could someone please go through the workings for this as the textbook I am working from simply gives the answer.

I did come up with an answer but it was wrong

Thanks!
2. Re: C4: Integration
3. Re: C4: Integration
What did you get when you integrated it ?
4. Re: C4: Integration
(Original post by boromir9111)
Must be a really silly mistake somewhere
5. Re: C4: Integration
Check the question, maybe you didn't write it down correctly?
6. Re: C4: Integration
(Original post by Nerdatious)
Must be a really silly mistake somewhere
Ahaha, such a silly mistake, all perfect. Look at after you have integrated.

you got

Check your work, it should be

this now gives

Look out for those 2's
Last edited by Tomcrease; 12-06-2012 at 21:31.
7. Re: C4: Integration
the integral should be

-14x + ln(2x+1) - 36ln(3-x) within the limits 1 and 0 this would give

-14 + ln3 - 36ln2 -(ln1-36ln3+0) = 37ln3 - 36ln2 -14?
Last edited by natninja; 12-06-2012 at 21:31.
8. Re: C4: Integration
(Original post by Tomcrease)
Ahaha, such a silly mistake, all perfect. Look at after you have integrated.

you got

Check your work, it should be

Look out for those 2's
Thanks! Think I must be overtired from my economics exam that I had today haha.

Need to be able to check my work myself!
9. Re: C4: Integration
(Original post by Nerdatious)
Must be a really silly mistake somewhere
It should be ln(2x+1) not ln(x+1) once you have integrated it. Other than that, it all looks perfect
10. Re: C4: Integration
Hey, has anyone got some help sheets on integration

im doing an intensive year course, and had to learn the whole of c4 in 5/6 weeks

any help would be greatly appreciated, which positive rep!