[Nerdatious]

Where the limits are 1 and 0 (I don't know how to put that in to the format above haha)
Giving you answer in the form pln3 +qln2 +r where p,q and r are integers.


The answer is 37ln3 - 36ln2 - 14.

Could someone please go through the workings for this as the textbook I am working from simply gives the answer.

I did come up with an answer but it was wrong

Thanks!

[boromir9111]

What have you tried so far? Post your working, please.

[shakey1]

What did you get when you integrated it ?

[Nerdatious]

(Original post by boromir9111)
What have you tried so far? Post your working, please.

Must be a really silly mistake somewhere

[NewCrack]

Check the question, maybe you didn't write it down correctly?

[Tomcrease]

(Original post by Nerdatious)
Must be a really silly mistake somewhere

Ahaha, such a silly mistake, all perfect. Look at after you have integrated.

you got

Check your work, it should be



this now gives





Look out for those 2's

[natninja]

the integral should be

-14x + ln(2x+1) - 36ln(3-x) within the limits 1 and 0 this would give

-14 + ln3 - 36ln2 -(ln1-36ln3+0) = 37ln3 - 36ln2 -14?

[Nerdatious]

(Original post by Tomcrease)
Ahaha, such a silly mistake, all perfect. Look at after you have integrated.

you got

Check your work, it should be



Look out for those 2's

Thanks! Think I must be overtired from my economics exam that I had today haha.

Need to be able to check my work myself!

[boromir9111]

(Original post by Nerdatious)
Must be a really silly mistake somewhere

It should be ln(2x+1) not ln(x+1) once you have integrated it. Other than that, it all looks perfect

[VRS]

Hey, has anyone got some help sheets on integration

im doing an intensive year course, and had to learn the whole of c4 in 5/6 weeks

any help would be greatly appreciated, which positive rep!