SHM graph
Physics and electronics discussion, revision, exam and homework help.
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Re: SHM graphI don't understand the question.
The graph shown is acceleration-time. It's a straight line because acceleration is directly proportional to displacement.
Edit: Sorry. Misread the question. See my 2nd answer with stronger lenses!Last edited by Stonebridge; 14-06-2012 at 22:16. -
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Re: SHM graphthats an acceleration vs displacement(Original post by Stonebridge)
I don't understand the question.
The graph shown is acceleration-time. It's a straight line because acceleration is directly proportional to displacement. -
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Re: SHM graphim waiting on stonebridges reply cus i need the answer aswell, and charge ur laptop btw..battery dying lol!(Original post by osake)
If I am asked to draw an acceleration-time graph, using the graph shown in the picture, would the acceleration-time graph be a sine curve or cosine curve? -
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Re: SHM graphI think I need a new pair of glasses.(Original post by Z.93)
thats an acceleration vs displacement
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Re: SHM graph2nd attempt at answer(Original post by osake)
If I am asked to draw an acceleration-time graph, using the graph shown in the picture, would the acceleration-time graph be a sine curve or cosine curve?
It depends where you take time= zero to be.
If you take time is zero at zero displacement, then at this point the acceleration is also zero. You would get a (negative) sine wave. (Value zero at t=0)Last edited by Stonebridge; 14-06-2012 at 22:32. -
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Re: SHM graphIn the mark scheme it says negative sine wave, but there is no indication in the question that we are suppose to take zero displacement to be t=0. Would we have to indicate in the graph that we have taken the initial displacement to be t=0?(Original post by Stonebridge)
2nd attempt at answer
It depends where you take time= zero to be.
If you take time is zero at zero displacement, then at this point the acceleration is also zero. You would get a (negative) sine wave. (Value zero at t=0) -
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Re: SHM graphIt does no harm to state this.
However, it's generally accepted, unless otherwise started, that the original displacement time graph for SHM is a sine wave.
If this is the case, then the acceleration time graph is a negative sine wave and the velocity time graph is a cosine wave.
