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SHM graph

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    If I am asked to draw an acceleration-time graph, using the graph shown in the picture, would the acceleration-time graph be a sine curve or cosine curve?
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    I don't understand the question.
    The graph shown is acceleration-time. It's a straight line because acceleration is directly proportional to displacement.

    Edit: Sorry. Misread the question. See my 2nd answer with stronger lenses!
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    (Original post by Stonebridge)
    I don't understand the question.
    The graph shown is acceleration-time. It's a straight line because acceleration is directly proportional to displacement.
    thats an acceleration vs displacement
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    (Original post by osake)
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    If I am asked to draw an acceleration-time graph, using the graph shown in the picture, would the acceleration-time graph be a sine curve or cosine curve?
    im waiting on stonebridges reply cus i need the answer aswell, and charge ur laptop btw..battery dying lol!
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    (Original post by Z.93)
    thats an acceleration vs displacement
    I think I need a new pair of glasses.
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    (Original post by osake)
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Name:	physics2.png 
Views:	42 
Size:	106.5 KB 
ID:	157072

    If I am asked to draw an acceleration-time graph, using the graph shown in the picture, would the acceleration-time graph be a sine curve or cosine curve?
    2nd attempt at answer

    It depends where you take time= zero to be.
    If you take time is zero at zero displacement, then at this point the acceleration is also zero. You would get a (negative) sine wave. (Value zero at t=0)
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    (Original post by Stonebridge)
    2nd attempt at answer

    It depends where you take time= zero to be.
    If you take time is zero at zero displacement, then at this point the acceleration is also zero. You would get a (negative) sine wave. (Value zero at t=0)
    In the mark scheme it says negative sine wave, but there is no indication in the question that we are suppose to take zero displacement to be t=0. Would we have to indicate in the graph that we have taken the initial displacement to be t=0?
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    It does no harm to state this.
    However, it's generally accepted, unless otherwise started, that the original displacement time graph for SHM is a sine wave.
    If this is the case, then the acceleration time graph is a negative sine wave and the velocity time graph is a cosine wave.

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Updated: June 17, 2012
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