You are Here: Home

# Temperature question

Announcements Posted on
Take our survey to be in with the chance of winning a £50 Amazon voucher or one of 5 x £10 Amazon vouchers 28-05-2016
1. A 500g ball of copper at 75ºC is cooled by dropping it into 300g of water at 20ºC. Assuming no heat is lost, what will be the equilibrium temperature?

For both the ball and water the difference in temperature will be the same right? 75-x=20+x, so x=27.5, so the equilibrium temp would be 47.5?
2. The mass plays a role, you have more of the warmer substance.
3. (Original post by nicatre)
The mass plays a role, you have more of the warmer substance.
Sorry I don't get your answer can you explain it in more detail?
4. If the weight and temps are all you are given, then i suppose it would be (Mass of Copper * Temp of Copper)+(Mass of water * Temp of water) All over the combined mass.
5. (Original post by osake)
Sorry I don't get your answer can you explain it in more detail?
I think he's saying that the mass of the copper ball should be equated for. For example, It'd cool down quicker if it was 100g instead of 500g.
6. (Original post by Naarim)
I think he's saying that the mass of the copper ball should be equated for. For example, It'd cool down quicker if it was 100g instead of 500g.
ah, well see i know that it should be equated for, i tried it yesterday, spent like 30 mins trying and didn't get the answer. Would usually not give up that fast but i cant afford to spend anymore time trying to answer the same question when the physic exams is tomorrow.
7. bump
9. (Original post by Hazza616)
10. bump
11. At equilibrium Qw = Qc

as Q = mc(t1-t2)

m(copper)c(copper)(t1 - T)=m(water)c(water)(T-t2)

Quite clearly you require the specific heat capacity. Without it this question is impossible.

## Register

Thanks for posting! You just need to create an account in order to submit the post
1. this can't be left blank
2. this can't be left blank
3. this can't be left blank

6 characters or longer with both numbers and letters is safer

4. this can't be left empty
1. Oops, you need to agree to our Ts&Cs to register

Updated: June 17, 2012
TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Today on TSR

### Don't be a half-term hermit

How to revise this week and still have a life

### Subjects you're happy to never do again

Poll
Study resources
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.