Cyclotron Question

Physics and electronics discussion, revision, exam and homework help.

This thread is sponsored by:
Announcements Posted on
Important: please read these guidelines before posting about exams on The Student Room 28-04-2013
Sign in to Reply
  1. Lolicakes's Avatar
    • New Member
    • Posts: 3
    Cyclotron Question
    Just trying to work out a question from my book, all help is appreciated.

    A 30cm radius cyclotron has a magnetic field of about 0.5T. Estimate the energy in MeV gained by accelerated protons.

    The answer given in the book is 1.08.
  2. teachercol's Avatar
    • Vengeful, Imperial Overlord of The Student Room
    • Location: Scarborough
    • Posts: 3,911
    Re: Cyclotron Question
    More info needed.
  3. Fleming92's Avatar
    • Junior Member
    • Location: StAndrews
    • Posts: 26
    Re: Cyclotron Question
    Ok, so first assume that protons will be moving in a perfect circular motion. (After all they are in a cyclotron :P)

    Then we can equate the centripital force due to the magnetic field, qvB, to that of the force of cicular motion from mechanics, ie F= (mv^2)/r

    equating these two expressions, alows you to cancel a v (velocity) from each side. After which you can re-arrange to get a value for v.

    (I got 1.437 x 10^ 7 m/s)

    Then simply put into the equation for kinetic energy, 1/2 m v^2 to get and enegry value in J.

    Then simply convert to MeV!
  4. teachercol's Avatar
    • Vengeful, Imperial Overlord of The Student Room
    • Location: Scarborough
    • Posts: 3,911
    Re: Cyclotron Question
    Seems reasonable.
Sign in to Reply
Share this discussion:  
Article updates
Moderators

We have a brilliant team of more than 60 volunteers looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

Reputation gems:
The Reputation gems seen here indicate how well reputed the user is, red gem indicate negative reputation and green indicates a good rep.
Post rating score:
These scores show if a post has been positively or negatively rated by our members.