[krisshP]

I'n stuck on a question. Please see the question on the attachement below. Angles ADC=136* by the way.


I can't use pythagoras' theorem as both triangles aren't right-angled traingles. This makes it hard for me.

How do I even start the question off?

[BabyMaths]

Do you know how to use the sine rule to find angle ADB?

[krisshP]

(Original post by BabyMaths)
Do you know how to use the sine rule to find angle ADB?

I'll give the sine rule a shot at this question.

Thanks for your help.

[cpdavis]

(Original post by krisshP)
I'n stuck on a question. Please see the question on the attachement below. Angles ADC=136* by the way.


I can't use pythagoras' theorem as both triangles aren't right-angled traingles. This makes it hard for me.

How do I even start the question off?

Split them into 2 triangles. What can you do?

[krisshP]

(Original post by BabyMaths)
Do you know how to use the sine rule to find angle ADB?

Would it be a good idea to calculate angle ADB, forming 16.39...*, and then working out angle DBA. After this then working out the area of triangle BAD by 0.5absinC formula????

Also after I work out the area for triangle BAD, how would I do the same for triangle DCB?

Thanks

[krisshP]

I got the area of triangle BAD to be 7999.157.....m^2.

[krisshP]

Thanks a lot

I found the answer to the question to be 17900m^2

[BabyMaths]

(Original post by krisshP)
I got the area of triangle BAD to be 7999.157.....m^2.

That's correct. Well done. (You have made 7^3 =343 posts.)

[krisshP]

(Original post by BabyMaths)
That's correct. Well done. (You have made 7^3 =343 posts.)

Lol Thanks I just noticed : Cya More Maths now!!!