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1. Area question
I'n stuck on a question. Please see the question on the attachement below. Angles ADC=136* by the way.

I can't use pythagoras' theorem as both triangles aren't right-angled traingles. This makes it hard for me.

How do I even start the question off?
2. Re: Area question
Do you know how to use the sine rule to find angle ADB?
3. Re: Area question
(Original post by BabyMaths)
Do you know how to use the sine rule to find angle ADB?
I'll give the sine rule a shot at this question.

4. Re: Area question
(Original post by krisshP)
I'n stuck on a question. Please see the question on the attachement below. Angles ADC=136* by the way.

I can't use pythagoras' theorem as both triangles aren't right-angled traingles. This makes it hard for me.

How do I even start the question off?
Split them into 2 triangles. What can you do?
5. Re: Area question
(Original post by BabyMaths)
Do you know how to use the sine rule to find angle ADB?
Would it be a good idea to calculate angle ADB, forming 16.39...*, and then working out angle DBA. After this then working out the area of triangle BAD by 0.5absinC formula????

Also after I work out the area for triangle BAD, how would I do the same for triangle DCB?

Thanks
6. Re: Area question
I got the area of triangle BAD to be 7999.157.....m^2.
7. Re: Area question
Thanks a lot

I found the answer to the question to be 17900m^2

8. Re: Area question
(Original post by krisshP)
I got the area of triangle BAD to be 7999.157.....m^2.
That's correct. Well done. (You have made 7^3 =343 posts.)
9. Re: Area question
(Original post by BabyMaths)
That's correct. Well done. (You have made 7^3 =343 posts.)
Lol Thanks I just noticed : Cya More Maths now!!!