How to do this?

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  1. sabre2th1's Avatar
    • Exalted and Worshipped Member
    • Location: Southampton
    • Posts: 1,046
    How to do this?
    y2/3 = 6x + 4lnx - 2

    I have to give my answer in the form of y2 = g(x)

    I find it tricky to convert y2/3 to y2.. Can someone show me how to do it?

    Thanks
  2. BabyMaths's Avatar
    • Peer Of The TSR Realm
    • Posts: 1,576
    Re: How to do this?
    (a^b)^c=a^{bc}
  3. ztibor's Avatar
    • Peer Of The TSR Realm
    • Location: Hungary
    • Posts: 1,540
    Re: How to do this?
    (Original post by sabre2th1)
    y2/3 = 6x + 4lnx - 2

    I have to give my answer in the form of y2 = g(x)

    I find it tricky to convert y2/3 to y2.. Can someone show me how to do it?

    Thanks
    Take both side of equation on the 3rd power
    \displaystyle \left (y^{\frac{2}{3}}\right )^3=y^2
    For RHS use
    \displaystyle \left (a+b+c)^3=a^3+b^3+c^3+3a^2c+3b^2  c+3ac^2+3bc^2+6abc
    where a=6x b=4lnx and c=-2
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