[kobrakaai]

(Original post by nikhil.shah)
I got 15.5, but can someone explain why this was correct??? I just kind of multiplied some numbers and got it lol...
Asking because my friend put quite a logical argument to me after that basically said because the pack was smaller (only 0.5 moles in 200g) than the 1 mol in 1kg the temp change should be smaller than 6.3 degrees

because this is 2.5 times more concentrated than 1 mol in 1 kg,
if it was as simple as your friends logic, we could just halve their given change, as we have half a mole
6.2 x 2.5 = 15.5

[TSRuser1234]

did anyone get a molar ratio of 1:2 NH3NO3 because the reaction only began when ten cm^3 of NH3 was added to 20cm^3 of HNO3?

[Emissionspectra]

(Original post by TSRuser1234)
did anyone get a molar ratio of 1:2 NH3NO3 because the reaction only began when ten cm^3 of NH3 was added to 20cm^3 of HNO3?

it was 1:1

[Bland New Eyes]

It was the same concentration of NH3 and HNO3 and both had 20cm^2 at equilibrium so I said it was 1:1 ?

[Emissionspectra]

(Original post by Bland New Eyes)
It was the same concentration of NH3 and HNO3 and both had 20cm^2 at equilibrium so I said it was 1:1 ?

That is correct.

[biolchem]

What did everyone do for the Le Chateliers principle question to reduce the amount of Iodine present? I wasn't sure so said add sodium thiosulphate to remove the iodine, but don't think that's right.

[nikhil.shah]

(Original post by biolchem)
What did everyone do for the Le Chateliers principle question to reduce the amount of Iodine present? I wasn't sure so said add sodium thiosulphate to remove the iodine, but don't think that's right.

You had to add NaOH, the OH- ions react and remove the H+ ions from solution so equilibrium would shift to the left to counteract the change


This was posted from The Student Room's iPhone/iPad App